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AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two
oppositely charged ions in the lattice is
  • a)
    335 pm
  • b)
    250 pm
  • c)
    200 pm
  • d)
    300 pm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
AB crystallizes in a body centred cubic lattice with edge length &lsqu...
The distance between opposite charges would be :

r=√3*a/4 here the edge length ,a is given by 387pm 

Implies r = √3 *387= 335 approximately ..
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Community Answer
AB crystallizes in a body centred cubic lattice with edge length &lsqu...
In bcc structure, 4r=a×square root of 3 , now, the distance between two opositely charged ion in the lattice =2r=a×sq.root of 3/2 ,, now put the value and you will get the answer
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AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between twooppositely charged ions in the lattice isa)335 pmb)250 pmc)200 pmd)300 pmCorrect answer is option 'A'. Can you explain this answer?
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