Six years ago, Seema was half of that of Rupa in age. Four years hence...
Let Seema's age at present be x years and Rupa's age be y years,
Now, according to the question,
(y - 6) = 2 (x - 6)
⇒ y - 6 = 2x - 12
or, 2x - y = 6 .....(1)
Also, x + 4/y + 4 = 3/5
or, 5x + 20 = 3y + 12
or, 5x - 3y = -8 .....(2)
From Equations (1) and (2), we get
x = 26 years and y = 46 years
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Six years ago, Seema was half of that of Rupa in age. Four years hence...
Let's assume Seema's present age is S years and Rupa's present age is R years.
Given that six years ago, Seema was half of that of Rupa in age.
So, six years ago, Seema's age = S - 6 years
And six years ago, Rupa's age = R - 6 years
According to the given information, four years hence the respective ratio of their ages would be 3:5.
So, four years from now, Seema's age = S + 4 years
And four years from now, Rupa's age = R + 4 years
According to the given information, the ratio of their ages after four years will be 3:5.
Therefore, we can write the equation as:
(S + 4) / (R + 4) = 3/5
Now, let's solve the equation step by step:
Cross multiplying the equation: 5(S + 4) = 3(R + 4)
5S + 20 = 3R + 12
Rearranging the equation: 5S - 3R = 12 - 20
5S - 3R = -8
Since we have two variables, we need one more equation to solve for their values.
Let's use the information given six years ago:
Seema's age six years ago = half of Rupa's age six years ago
(S - 6) = (1/2)(R - 6)
Simplifying the equation: 2(S - 6) = R - 6
2S - 12 = R - 6
Rearranging the equation: 2S - R = -6 + 12
2S - R = 6
Now, we have a system of two equations:
5S - 3R = -8 ...(Equation 1)
2S - R = 6 ...(Equation 2)
Solving these two equations simultaneously will give us the values of S and R.
Multiplying Equation 2 by 3, we get:
6S - 3R = 18 ...(Equation 3)
Subtracting Equation 3 from Equation 1, we get:
(5S - 3R) - (6S - 3R) = -8 - 18
Simplifying the equation: -S = -26
Dividing by -1 on both sides, we get:
S = 26
Substituting the value of S in Equation 2, we get:
2(26) - R = 6
52 - R = 6
R = 52 - 6
R = 46
Therefore, Rupa's present age is 46 years.
Six years ago, Seema was half of that of Rupa in age. Four years hence...
Given that 6 years ago Seema is half of that of Rupa so Ife we take (1/2 ) 2 is Rupa and 1 is Seema (1 is half of 2).
now Seema is 1 and Rupa is 2 ( which is 6 years ago ratio).
it is also given that 4 years aftr their ratio is 3:5(Seema3,rupa5)
before 6 years and aftr 4 years (6+4= 10years).
S. R.
6yrs ago 1. :. 2.
+10yrs. +10yrs
aftr 4 yrs. 3. :. 5. (cross multiply(1*5=5 ,
3*2=6)(6-5=1))
1. :. 20 (cm(5*10=50
3*10=30)(50-30=20))
for 1= 20 then w.r.to given 6yr ago ratio 1:2
for 1= 1*20=20 , for 2 = 2*20=40(6yrs ago ages of Seema and Rupa are 20 and 40 respectively).
present ages ( seema's age is 20+6=26 and Rupa's age is 40+6= 46 years).
aftr 4 years (Seema age 26+4=30 , Rupa age 46+4= 50)(given ratio 3:5).
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