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How many different insertion sequences of the key values using the same hash function and linear probing will result in the hash table shown above?

  • a)
    10

  • b)
    20

  • c)
    30

  • d)
    40

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
How many different insertion sequences of the key values using the sam...
In a valid insertion sequence, the elements 42, 23 and 34 must appear before 52 and 33, and 46 must appear before 33.
Total number of different sequences = 3! x 5 = 30
In the above expression, 3! is for elements 42, 23 and 34 as they can appear in any order, and 5 is for element 46 as it can appear at 5 different places.
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Most Upvoted Answer
How many different insertion sequences of the key values using the sam...
Row of many is putting advice the parallel square and power of square 30 is correct answer
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Community Answer
How many different insertion sequences of the key values using the sam...
For the above hash table to occur, collision occurs for 52 and 33. That means, 42 and 23 must always appear before 52 and 33. Also note that 34 should always come before 52 and 33, else 52 and 33 may occupy 34's place. Therefore 42,23, and 34 should appear before 52 and 33. Hence 42, 23 and 34 can occur in 3! ways.
Now notice that 52 should come before, and finally 46 can appear at 5 different places.
Therefore, total number of different sequences = 3! x 5 = 30
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