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For Charles’ law, graphical representation between log V and log T under isobaric condition is shown below for equation V = kTQ.Volume V = constant k, whena)T = 0ocb)T = 273occ)T = 0Kd)T = -272ocCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about For Charles’ law, graphical representation between log V and log T under isobaric condition is shown below for equation V = kTQ.Volume V = constant k, whena)T = 0ocb)T = 273occ)T = 0Kd)T = -272ocCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For Charles’ law, graphical representation between log V and log T under isobaric condition is shown below for equation V = kTQ.Volume V = constant k, whena)T = 0ocb)T = 273occ)T = 0Kd)T = -272ocCorrect answer is option 'D'. Can you explain this answer?.

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