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The initial rates of reaction for the equation, 2A + B → Products.
Products were determined under various initial concentrations of reactants.
Thus, rate law is equal to
  • a)
    k[A][B]
  • b)
    k[A][B]2
  • c)
     k[A]
  • d)
     k[B]
Correct answer is option 'C'. Can you explain this answer?
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The initial rates of reaction for the equation, 2A + B → Product...
Let order w.r.t. A = a, order w.r.t. B = b

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The initial rates of reaction for the equation, 2A + B → Product...
Let order w.r.t. A = a, order w.r.t. B = b

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The initial rates of reaction for the equation, 2A + B → Product...
Case 1&2 - concentration (A) increase tow multiplcation . concń. (B) is constant . rate increase two multiplcation then rate = k(A) case 1&3 - concń. (A) is a constant. concń. (B) increase tow multiplcation. but not change in rate . thn rate = k(A) , over all order = 1
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The initial rates of reaction for the equation, 2A + B → Products.Products were determined under various initial concentrations of reactants.Thus, rate law is equal toa)k[A][B]b)k[A][B]2c)k[A]d)k[B]Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The initial rates of reaction for the equation, 2A + B → Products.Products were determined under various initial concentrations of reactants.Thus, rate law is equal toa)k[A][B]b)k[A][B]2c)k[A]d)k[B]Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The initial rates of reaction for the equation, 2A + B → Products.Products were determined under various initial concentrations of reactants.Thus, rate law is equal toa)k[A][B]b)k[A][B]2c)k[A]d)k[B]Correct answer is option 'C'. Can you explain this answer?.
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