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When driving to college Vedant's average speed for his trip is 20 km/hr on his return up along the same route there is less traffic and the average speed is 40 km/hr what is the average speed for Vedant's trip?
Most Upvoted Answer
When driving to college Vedant's average speed for his trip is 20 km/h...
Calculating Vedant's Average Speed for the Trip

To calculate the average speed for Vedant's trip, we need to use the formula:

Average Speed = Total Distance / Total Time

Calculating Total Distance

As Vedant is traveling along the same route for both his journey to college and his return, the total distance covered will be the same. So, we need to calculate the total distance for his trip.

Let's assume that the distance between Vedant's home and college is 'D' kilometers.

So, the total distance covered by Vedant for the round trip will be:

Total Distance = D + D = 2D

Calculating Total Time

To calculate the total time taken by Vedant for his trip, we need to use the formula:

Total Time = Time Taken for Going to College + Time Taken for Returning

Let's assume that Vedant takes 't1' hours to reach college and 't2' hours to return home.

So, the total time taken by Vedant for his trip will be:

Total Time = t1 + t2

Calculating Average Speed

Now, we can substitute the values of Total Distance and Total Time in the formula for Average Speed.

Average Speed = (2D) / (t1 + t2)

We know that Vedant's average speed while driving to college is 20 km/hr, and his average speed while returning home is 40 km/hr.

So, we can use the formula:

Average Speed = (2 x 20 x 40) / (20 + 40)

Average Speed = (1600) / (60)

Average Speed = 26.67 km/hr

Therefore, the average speed for Vedant's trip is 26.67 km/hr.
Community Answer
When driving to college Vedant's average speed for his trip is 20 km/h...
Average speed = total distance / total time... suppose distance between home to college is D..... ==> t1 = D / V1 & t2= D / V2 ===> Average speed = D + D / t1 + t2===> = 2 D / [ ( D / V1 ) + ( D / V2 ) ] ==> = 2 / [ ( 1 / 20 ) + ( 1/ 40 ) ] ==> = 2 / [ ( 40 + 20 ) / 40 * 20 ] ==> = 2 / [ 60 / 800 ] ==> = 1600 / 60==> = 26.67 km / hr.. IS THE YOUR ANSWER...💯💯💯💯
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When driving to college Vedant's average speed for his trip is 20 km/hr on his return up along the same route there is less traffic and the average speed is 40 km/hr what is the average speed for Vedant's trip?
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When driving to college Vedant's average speed for his trip is 20 km/hr on his return up along the same route there is less traffic and the average speed is 40 km/hr what is the average speed for Vedant's trip? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about When driving to college Vedant's average speed for his trip is 20 km/hr on his return up along the same route there is less traffic and the average speed is 40 km/hr what is the average speed for Vedant's trip? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When driving to college Vedant's average speed for his trip is 20 km/hr on his return up along the same route there is less traffic and the average speed is 40 km/hr what is the average speed for Vedant's trip?.
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