A constant current I is maintained in a solenoid. Which of the followi...
Rate of joule heating will not increase since the current is constant in the solenoid.
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A constant current I is maintained in a solenoid. Which of the followi...
Magnetic field is directly proportional to permiability and when iron rod is inserted the relative permeability changes and thus magnetic field , self inductance is proportional to flux which is proportional to magnetic field and thus follow above explanation, and remaining last option rate of heating =I²R and both these factors doesn't get affected by iron rod , and hence this is correct option.
A constant current I is maintained in a solenoid. Which of the followi...
Explanation:
When an iron rod is inserted into the solenoid along its axis, it affects various quantities associated with the solenoid. Let's discuss each option one by one to understand the changes that occur.
a) Magnetic field at the centre:
When an iron rod is inserted into the solenoid, it increases the magnetic field at the center of the solenoid. This is because the iron rod becomes magnetized due to the magnetic field produced by the solenoid. The magnetic field lines pass through the iron rod, creating a stronger magnetic field at the center.
b) Self-inductance of the solenoid:
The self-inductance of the solenoid is determined by its physical properties, such as the number of turns, length, and cross-sectional area. Inserting an iron rod does not directly affect these properties, so the self-inductance of the solenoid remains unchanged.
c) Magnetic flux linked with the solenoid:
The magnetic flux linked with the solenoid is directly proportional to the magnetic field passing through the solenoid and the number of turns. As the magnetic field increases due to the presence of the iron rod, the magnetic flux linked with the solenoid also increases.
d) Rate of joule heating:
Joule heating is the process in which electrical energy is converted into heat due to the resistance of the material. When an iron rod is inserted into the solenoid, it increases the overall resistance of the circuit. As a result, the rate of joule heating increases because more heat is generated due to the increased resistance.
Therefore, the correct answer is option 'D' - Rate of joule heating.