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The locus of centre of the circle which cuts orthogonally the circle x^2+ y^2 - 20x + 4 =0 and which touches x =2 is A x^2=16y B x^2= 16x + 4 C y^2= 16x D y^2=16x+4? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The locus of centre of the circle which cuts orthogonally the circle x^2+ y^2 - 20x + 4 =0 and which touches x =2 is A x^2=16y B x^2= 16x + 4 C y^2= 16x D y^2=16x+4? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The locus of centre of the circle which cuts orthogonally the circle x^2+ y^2 - 20x + 4 =0 and which touches x =2 is A x^2=16y B x^2= 16x + 4 C y^2= 16x D y^2=16x+4?.

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