A particle is moving so that it's displacement is given as s =t3-6t2+3...
Explanation:
To find the velocity of the particle when its acceleration is zero, we need to differentiate the displacement equation twice with respect to time to obtain the acceleration equation. Once we get the acceleration equation, we can set it equal to zero and solve for the time at which it occurs. Then we can substitute this time into the velocity equation to obtain the velocity at that instant.
Derivation:
Step 1: Differentiate the displacement equation to obtain the velocity equation:
s = t3-6t2+3t+4
v = ds/dt = 3t2-12t+3
Step 2: Differentiate the velocity equation to obtain the acceleration equation:
a = dv/dt = 6t-12
Step 3: Set the acceleration equation equal to zero and solve for the time at which it occurs:
a = 6t-12 = 0
t = 2 seconds
Step 4: Substitute the time into the velocity equation to obtain the velocity at that instant:
v = 3t2-12t+3
v = 3(2)2-12(2)+3
v = -15 m/s
Conclusion:
The velocity of the particle at the instant when its acceleration is zero is -15 m/s.
A particle is moving so that it's displacement is given as s =t3-6t2+3...
Differentiate it two times and put it equal to zero ds/dt=3t^2-12t+3 d^2s/dt^2 = 6t-12 6t-12=0 t=2 sec answer= 2sec