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A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will be
  • a)
    120 N
  • b)
    130 N
  • c)
    150N
  • d)
    115 N
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The...
As 250N is applied to move the cyclist and cycle, and lets say some frictional force f is acting upon it.
Thus we get 250 - f = 30 x 4 =120
Thus we get f = 130N
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A cyclist of mass 30 kg exerts a force of 250 N to move his cycle. The acceleration is 4 ms−2. The force of friction between the road and tyres will bea)120 Nb)130 Nc)150Nd)115 NCorrect answer is option 'B'. Can you explain this answer?
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