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A bullet of mass 0.01 kg is fired from a rifle. The bullet takes 0.003 s to move through the barrel and leaves with a velocity of 300 ms–1. The acceleration acting on the bullet is :
  • a)
    10,000 ms–2
  • b)
    100,000 ms–2
  • c)
    1000,000 ms–2
  • d)
    1000 ms–2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A bullet of mass 0.01 kg is fired from a rifle. The bullet takes 0.003...
GIVEN,

MASS OF BULLET(m) = 10G = 10/1000 = 0.01KG

TIME TAKEN(t) = 0.003 SECS.

INITIAL VELOCITY (u) =300 M/S

FINAL VELOCITY (v) = 0.

ACCELERATION (a) =?

FORCE (F) = ?

BY USING 1ST EQUATION OF MOTION,

WE GET,

v = u + at

300 = 0 + a X 0.003

300 = a X 0.003

300/0.003 = a

100,000 = a

OR

a = 100,000 M/S2.

NOW,

WE KNOW THAT,

F = m X a

= 0.01 X 100,000

= 1000 N..
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Most Upvoted Answer
A bullet of mass 0.01 kg is fired from a rifle. The bullet takes 0.003...
Acceleration is defined as the rate of change of velocity with respect to time. It is calculated by dividing the change in velocity by the time taken. In this case, the bullet starts from rest and reaches a velocity of 300 m/s in 0.003 s.

Therefore, the change in velocity is:

Δv = 300 m/s - 0 m/s = 300 m/s

The time taken is given as 0.003 s.

Now, we can use the formula for acceleration:

a = Δv / t

Substituting the values, we get:

a = 300 m/s / 0.003 s = 100,000 m/s^2

So, the acceleration acting on the bullet is 100,000 m/s^2.

Therefore, the correct answer is option 'B'.
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Community Answer
A bullet of mass 0.01 kg is fired from a rifle. The bullet takes 0.003...
Mass of bullet =0.01kgTime taken =0.003sV=300m/sAcceleration =v---u/t =300--0/0.003 =300/0.003 =100×1000 =100000m/s square
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A bullet of mass 0.01 kg is fired from a rifle. The bullet takes 0.003 s to move through the barrel and leaves with a velocity of 300 ms–1. The acceleration acting on the bullet is :a)10,000 ms–2b)100,000 ms–2c)1000,000 ms–2d)1000 ms–2Correct answer is option 'B'. Can you explain this answer?
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