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The displacement of a particle moving in a straight line is described by the relation, s =6 + 12t -2(t square) . here s is in metre and t is in second. the distance covered by particle in first 5 sec is (a) 20m (b)32m (c)24m (d)26m?
Most Upvoted Answer
The displacement of a particle moving in a straight line is described ...
In straight line distance equals displacement
Ds/Dt=12-4t=V(t)
V(5)= -8m/s means the particle moves in opposite direction.
S(5sec)=6+12(5)-2(5^2)=16m
distance become twice of displacement
S(distance)=32m
Ds/Dt=12-4t=V(t)
V(5)= -8m/s means the particle moves in opposite direction.
S(5sec)=6+12(5)-2(5^2)=16m
distance become twice of displacement
S(distance)=32m
Community Answer
The displacement of a particle moving in a straight line is described ...
Given information:
The displacement of a particle moving in a straight line is described by the relation:
s = 6 + 12t - 2t^2
Explanation:
To find the distance covered by the particle in the first 5 seconds, we need to calculate the total length of the path traveled by the particle within this time frame.
Step 1: Find the displacement of the particle
The given equation represents the displacement of the particle at any given time t. To find the displacement within the first 5 seconds, we substitute t = 5 into the equation:
s = 6 + 12(5) - 2(5^2)
s = 6 + 60 - 2(25)
s = 6 + 60 - 50
s = 16 meters
Therefore, the displacement of the particle within the first 5 seconds is 16 meters.
Step 2: Find the distance covered
The distance covered by the particle is the absolute value of the displacement. Since displacement can be positive or negative depending on the direction of motion, we take the absolute value to obtain the distance.
Distance = |16| = 16 meters
Step 3: Determine the correct answer
Comparing the calculated distance with the options given, we can see that the correct answer is (d) 26m.
Conclusion:
The distance covered by the particle in the first 5 seconds is 16 meters.
The displacement of a particle moving in a straight line is described by the relation:
s = 6 + 12t - 2t^2
Explanation:
To find the distance covered by the particle in the first 5 seconds, we need to calculate the total length of the path traveled by the particle within this time frame.
Step 1: Find the displacement of the particle
The given equation represents the displacement of the particle at any given time t. To find the displacement within the first 5 seconds, we substitute t = 5 into the equation:
s = 6 + 12(5) - 2(5^2)
s = 6 + 60 - 2(25)
s = 6 + 60 - 50
s = 16 meters
Therefore, the displacement of the particle within the first 5 seconds is 16 meters.
Step 2: Find the distance covered
The distance covered by the particle is the absolute value of the displacement. Since displacement can be positive or negative depending on the direction of motion, we take the absolute value to obtain the distance.
Distance = |16| = 16 meters
Step 3: Determine the correct answer
Comparing the calculated distance with the options given, we can see that the correct answer is (d) 26m.
Conclusion:
The distance covered by the particle in the first 5 seconds is 16 meters.
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The displacement of a particle moving in a straight line is described by the relation, s =6 + 12t -2(t square) . here s is in metre and t is in second. the distance covered by particle in first 5 sec is (a) 20m (b)32m (c)24m (d)26m?
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The displacement of a particle moving in a straight line is described by the relation, s =6 + 12t -2(t square) . here s is in metre and t is in second. the distance covered by particle in first 5 sec is (a) 20m (b)32m (c)24m (d)26m? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The displacement of a particle moving in a straight line is described by the relation, s =6 + 12t -2(t square) . here s is in metre and t is in second. the distance covered by particle in first 5 sec is (a) 20m (b)32m (c)24m (d)26m? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The displacement of a particle moving in a straight line is described by the relation, s =6 + 12t -2(t square) . here s is in metre and t is in second. the distance covered by particle in first 5 sec is (a) 20m (b)32m (c)24m (d)26m?.
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