Given information:
- Mass of organic compound = 1.6 g
- Mass of carbon dioxide produced = 4.4 g

To find:
- Percentage of carbon in the organic compound

Solution:
1. Calculate the molar mass of carbon dioxide (CO2):
- The atomic mass of carbon (C) = 12.01 g/mol
- The atomic mass of oxygen (O) = 16.00 g/mol
- Molar mass of carbon dioxide (CO2) = (12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol

2. Determine the number of moles of carbon dioxide produced:
- Moles of carbon dioxide = Mass of carbon dioxide / Molar mass of carbon dioxide
- Moles of carbon dioxide = 4.4 g / 44.01 g/mol = 0.1 mol

3. Since carbon dioxide (CO2) is produced by the combustion of the organic compound, the number of moles of carbon in the organic compound is equal to the number of moles of carbon dioxide produced.

4. Calculate the molar mass of carbon (C):
- The molar mass of carbon (C) = 12.01 g/mol

5. Determine the mass of carbon in the organic compound:
- Mass of carbon = Moles of carbon x Molar mass of carbon
- Mass of carbon = 0.1 mol x 12.01 g/mol = 1.201 g

6. Calculate the percentage of carbon in the organic compound:
- Percentage of carbon = (Mass of carbon / Mass of organic compound) x 100
- Percentage of carbon = (1.201 g / 1.6 g) x 100 = 75.06%

Answer:
The percentage of carbon in the organic compound is approximately 75.06%.