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How much work should be done on a bicycle of mass 20kg to increase its speed from 2 m s -¹ to 5 m s-¹ (Ignore air resistance and friction . can you explain this question?
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How much work should be done on a bicycle of mass 20kg to increase its...


Calculating the Work Done on a Bicycle

To calculate the work done on a bicycle of mass 20kg to increase its speed from 2 m/s to 5 m/s, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy.

Initial and Final Kinetic Energies
- Initial kinetic energy (KEi) = 0.5 * mass * initial velocity^2
- Initial KEi = 0.5 * 20kg * (2 m/s)^2 = 40 Joules
- Final kinetic energy (KEf) = 0.5 * mass * final velocity^2
- Final KEf = 0.5 * 20kg * (5 m/s)^2 = 250 Joules

Change in Kinetic Energy
- Change in kinetic energy = KEf - KEi
- Change in kinetic energy = 250J - 40J = 210 Joules

Work Done
- Work done = Change in kinetic energy
- Work done = 210 Joules

Therefore, the work done on the bicycle to increase its speed from 2 m/s to 5 m/s is 210 Joules. This work is required to accelerate the bicycle and increase its kinetic energy.
Community Answer
How much work should be done on a bicycle of mass 20kg to increase its...
W = F *S

W = 1/2m(v^2 -u^2)

W =1/2 *20(5^2 -2^2)

W =210 J
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How much work should be done on a bicycle of mass 20kg to increase its speed from 2 m s -¹ to 5 m s-¹ (Ignore air resistance and friction . can you explain this question?
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