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Which of the following will have the highest coagulating power for As2S3 colloids?
- a)Al3+
- b)Na+
- c)PO43-
- d)PO42-
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Which of the following will have the highest coagulating power for As2...
The correct answer is Option A.
AS2S3 is an anionic sol (negative sol) hence coagulation will depend on coagulating power of cation , which is directly proportional to the valency of the cation (Hardy-Schulze rule).
Hence positive ions having maximum amount of charge will have more coagulation thus, Al3+ have maximum coagulating power.
Hence positive ions having maximum amount of charge will have more coagulation thus, Al3+ have maximum coagulating power.
Most Upvoted Answer
Which of the following will have the highest coagulating power for As2...
Coagulating Power of Al3+ for As2S3 Colloids
As2S3 colloids are negatively charged due to the presence of S2- ions on their surface. To coagulate these colloids, positively charged ions need to be added, which can neutralize the negative charge and cause the particles to come together.
Out of the given options, Al3+ has the highest coagulating power for As2S3 colloids due to the following reasons:
1. Charge density: Al3+ has a higher charge density than Na+ and PO43-, which means that it can attract and neutralize the negatively charged S2- ions on the surface of As2S3 colloids more effectively.
2. Hydrolysis: Al3+ undergoes hydrolysis in aqueous solutions, which means that it reacts with water molecules to form hydrated Al3+ ions and H+ ions. The H+ ions can further neutralize the negative charge on the colloids, leading to their coagulation.
3. Complex formation: Al3+ can form complexes with S2- ions, which can further enhance the coagulating power of Al3+ for As2S3 colloids.
Therefore, Al3+ is the best option for coagulating As2S3 colloids.
As2S3 colloids are negatively charged due to the presence of S2- ions on their surface. To coagulate these colloids, positively charged ions need to be added, which can neutralize the negative charge and cause the particles to come together.
Out of the given options, Al3+ has the highest coagulating power for As2S3 colloids due to the following reasons:
1. Charge density: Al3+ has a higher charge density than Na+ and PO43-, which means that it can attract and neutralize the negatively charged S2- ions on the surface of As2S3 colloids more effectively.
2. Hydrolysis: Al3+ undergoes hydrolysis in aqueous solutions, which means that it reacts with water molecules to form hydrated Al3+ ions and H+ ions. The H+ ions can further neutralize the negative charge on the colloids, leading to their coagulation.
3. Complex formation: Al3+ can form complexes with S2- ions, which can further enhance the coagulating power of Al3+ for As2S3 colloids.
Therefore, Al3+ is the best option for coagulating As2S3 colloids.
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Community Answer
Which of the following will have the highest coagulating power for As2...
Concept: Hardy Scruze rule.Explanation:According to hardy scruze rule :- The more positively highly charged cation will have the more coagulating power towards the negative charge sol. So,As2S2 sol is negatively charged sol , Al3+ has the greater charge . Therefore Al3+ is most effective in coagulation of the sol As2S3.Hence ,correct answer is (A).
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Which of the following will have the highest coagulating power for As2S3colloids?a)Al3+b)Na+c)PO43-d)PO42-Correct answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Which of the following will have the highest coagulating power for As2S3colloids?a)Al3+b)Na+c)PO43-d)PO42-Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following will have the highest coagulating power for As2S3colloids?a)Al3+b)Na+c)PO43-d)PO42-Correct answer is option 'A'. Can you explain this answer?.
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