Question Description
t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared
according to
the Class 12 exam syllabus. Information about t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer?.
Solutions for t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice t1/4 can be taken as the time taken for the concentration of a reactant to drop to 3/4 of its initial value.If the rate constant for a first order reaction is K, t1/4 can be written as – [AIEEE-2005]a)0.29/Kb)0.10/Kc)0.75/Kd)0.69/KCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.