When the distance between two charged particle is halved, the force be...
The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
When the distance between two charged particle is halved, the force be...
Explanation:
Coulomb's Law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically,
F ∝ q1q2/d^2
Where F is the force between the particles, q1 and q2 are the charges of the particles, and d is the distance between them.
When the distance between the two charged particles is halved, the new distance becomes 1/2d. Substituting this value in the above equation, we get:
F' ∝ q1q2/(1/2d)^2
F' ∝ q1q2/[(1/2)^2d^2]
F' ∝ q1q2/[(1/4)d^2]
F' ∝ 4q1q2/d^2
Therefore, the force between the particles becomes four times the original force. Hence, the correct answer is option D (Four times).
Conclusion:
When the distance between two charged particles is halved, the force between them becomes four times.