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If Q =2 coloumb and force on it is F=100 newtons , Then the value of field intensity will be
- a)100 N/C
- b)50 N/C
- c)200 N/C
- d)10 N/C
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If Q =2 coloumb and force on it is F=100 newtons , Then the value of f...
Electric force on a charge q placed in a region o electric field intensity is E and it is given by F = qE.
In this case, F = 100 N and q = 2 C.
So, E=F/q=100N/2C=50 N/C.
Hence, the value of field intensity will be 50 N/C.
In this case, F = 100 N and q = 2 C.
So, E=F/q=100N/2C=50 N/C.
Hence, the value of field intensity will be 50 N/C.
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Community Answer
If Q =2 coloumb and force on it is F=100 newtons , Then the value of f...
Field intensity, also known as electric field strength, is defined as the force experienced by a unit positive charge placed in an electric field. It is given by the equation:
E = F/Q
where E is the electric field intensity, F is the force on the charge, and Q is the charge.
Given that Q = 2 C and F = 100 N, we can substitute these values into the equation to find the electric field intensity:
E = 100 N / 2 C = 50 N/C
Therefore, the correct answer is option 'B' - 50 N/C.
Explanation:
Let's break down the steps to understand why the answer is 50 N/C:
1. Electric field intensity (E) is defined as the force (F) experienced by a unit positive charge (Q) placed in an electric field.
2. In this case, the force (F) on the charge is given as 100 N.
3. The charge (Q) is given as 2 C.
4. We can substitute these values into the equation for electric field intensity: E = F/Q.
5. Plugging in the values, we get E = 100 N / 2 C = 50 N/C.
6. Therefore, the electric field intensity in this case is 50 N/C.
To summarize, the electric field intensity is calculated by dividing the force on a charge by the magnitude of the charge. In this case, with a force of 100 N and a charge of 2 C, the electric field intensity is 50 N/C.
E = F/Q
where E is the electric field intensity, F is the force on the charge, and Q is the charge.
Given that Q = 2 C and F = 100 N, we can substitute these values into the equation to find the electric field intensity:
E = 100 N / 2 C = 50 N/C
Therefore, the correct answer is option 'B' - 50 N/C.
Explanation:
Let's break down the steps to understand why the answer is 50 N/C:
1. Electric field intensity (E) is defined as the force (F) experienced by a unit positive charge (Q) placed in an electric field.
2. In this case, the force (F) on the charge is given as 100 N.
3. The charge (Q) is given as 2 C.
4. We can substitute these values into the equation for electric field intensity: E = F/Q.
5. Plugging in the values, we get E = 100 N / 2 C = 50 N/C.
6. Therefore, the electric field intensity in this case is 50 N/C.
To summarize, the electric field intensity is calculated by dividing the force on a charge by the magnitude of the charge. In this case, with a force of 100 N and a charge of 2 C, the electric field intensity is 50 N/C.
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