100 mL of a colloidal solution is completely precipitated by addition of 5 mL of 1 M Nacl solution . Calculate the coagulation value of Nacl .a)200 b)100c)50d)25Correct answer is option 'C'. Can you explain this answer?

Question

Answer

Coagulation value is the millimoles of an electrolyte that must be added to 1 L of a colloidal solution for complete coagulation .Therefore , 5 mL of 1 M NaCl = 1/1000 X 5=0.005 OR 5 m moles .

100 mL of a colloidal solution require NaCl for complete coagulation = 50 m moles

Therefore , Coagulation value of NaCl = 50

Answer

Answer

Coagulation value is the millimoles of an electrolyte that must be added to 1 L of a colloidal solution for complete coagulation. Therefore , 5 mL of 1 M NaCl = 1/1000x5 = 0.005 or 5 m moles .

100 mL of a colloidal solution require NaCl for complete coagulation = 50 m moles

Therefore , Coagulation value of NaCl = 50

Answer

Coagulation is the process of destabilizing and precipitating colloidal particles, resulting in the formation of larger aggregates or flocs. The coagulation value of a substance is the minimum concentration of that substance required to cause coagulation of a given colloidal solution.

Given:
Volume of colloidal solution = 100 mL
Volume of NaCl solution added = 5 mL
Concentration of NaCl solution = 1 M

To calculate the coagulation value of NaCl, we need to determine the concentration of NaCl at which complete coagulation occurs.

Let's assume that the coagulation value of NaCl is x M. This means that when the concentration of NaCl reaches x M, complete coagulation of the colloidal solution occurs.

The total volume of the solution after adding NaCl is 100 mL + 5 mL = 105 mL.

To calculate the concentration of NaCl after adding 5 mL of 1 M solution, we can use the equation:

(M1)(V1) = (M2)(V2)

Where:
M1 = initial concentration of NaCl solution
V1 = initial volume of NaCl solution
M2 = final concentration of NaCl solution
V2 = final volume of NaCl solution

Substituting the values:
(1 M)(5 mL) = (M2)(105 mL)

Simplifying the equation:
5 M mL = 105 M2 mL

Dividing both sides of the equation by 105 mL:
5 M = M2

Therefore, the concentration of NaCl after adding 5 mL of 1 M solution is 5 M.

Since the coagulation value of NaCl is the minimum concentration required for complete coagulation, and we have found that a concentration of 5 M is sufficient for coagulation, the coagulation value of NaCl in this case is 5 M.

However, the options listed in the question do not include 5 M. It's possible that there is an error in the options provided, and the correct answer may not be among the given choices.

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