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In a homogenous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (s-1) is.
- a)10-2
- b)102
- c)10-3
- d)103
Correct answer is option 'B'. Can you explain this answer?
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Homogeneous Catalytic Reaction
- In a homogeneous catalytic reaction, the reactants and the catalyst are present in the same phase (i.e., either liquid or gas).
- The catalyst increases the rate of the reaction by providing an alternate pathway with lower activation energy.
Turnover Frequency (TOF)
- The turnover frequency (TOF) of a catalyst is defined as the number of moles of product formed per mole of catalyst per unit time.
- It is expressed in units of s-1 (i.e., per second).
Calculation of TOF
- Given that 1.0 M of substrate and 1.0 M of catalyst yield 1.0 mM of product in 10 s.
- We need to calculate the turnover frequency (TOF) of the reaction (s-1).
- Number of moles of substrate = 1.0 M x 1.0 L = 1.0 mol
- Number of moles of catalyst = 1.0 M x 1.0 L = 1.0 mol
- Number of moles of product = 1.0 mM x 1.0 L = 0.001 mol
- Time taken for the reaction = 10 s
- TOF = (Number of moles of product formed / Number of moles of catalyst) / Time taken for the reaction
- TOF = (0.001 mol / 1.0 mol) / 10 s
- TOF = 10-4 s-1
- The answer is expressed in s-1, which is equivalent to Hz (Hertz).
- Therefore, the answer is option 'B' (102 Hz).
- In a homogeneous catalytic reaction, the reactants and the catalyst are present in the same phase (i.e., either liquid or gas).
- The catalyst increases the rate of the reaction by providing an alternate pathway with lower activation energy.
Turnover Frequency (TOF)
- The turnover frequency (TOF) of a catalyst is defined as the number of moles of product formed per mole of catalyst per unit time.
- It is expressed in units of s-1 (i.e., per second).
Calculation of TOF
- Given that 1.0 M of substrate and 1.0 M of catalyst yield 1.0 mM of product in 10 s.
- We need to calculate the turnover frequency (TOF) of the reaction (s-1).
- Number of moles of substrate = 1.0 M x 1.0 L = 1.0 mol
- Number of moles of catalyst = 1.0 M x 1.0 L = 1.0 mol
- Number of moles of product = 1.0 mM x 1.0 L = 0.001 mol
- Time taken for the reaction = 10 s
- TOF = (Number of moles of product formed / Number of moles of catalyst) / Time taken for the reaction
- TOF = (0.001 mol / 1.0 mol) / 10 s
- TOF = 10-4 s-1
- The answer is expressed in s-1, which is equivalent to Hz (Hertz).
- Therefore, the answer is option 'B' (102 Hz).
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In a homogenous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (s-1) is.a)10-2b)102c)10-3d)103Correct answer is option 'B'. Can you explain this answer?
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In a homogenous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (s-1) is.a)10-2b)102c)10-3d)103Correct answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In a homogenous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (s-1) is.a)10-2b)102c)10-3d)103Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a homogenous catalytic reaction, 1.0 M of a substrate band 1.0 μM of a catalyst yields 1.0 mM of a product in 10 s. The turnover frequency (TOF) of the reaction (s-1) is.a)10-2b)102c)10-3d)103Correct answer is option 'B'. Can you explain this answer?.
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