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A circular disc of radius 'r' is submerged vertically in a static fluidup to a depth 'h' from the free surface. If h > r, then the positionof centre of pressure will: 
  • a)
    Be directly proportional to h
  • b)
    Be inversely proportional of h
  • c)
    Be directly proportional to r
  • d)
    Not be a function of h or r
Correct answer is option 'A'. Can you explain this answer?
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A circular disc of radius 'r' is submerged vertically in a sta...
Ans. (a)
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A circular disc of radius 'r' is submerged vertically in a sta...

Concept Explanation:

The position of the center of pressure on a submerged surface is the point through which the total pressure force acts on the surface. In the case of a circular disc submerged vertically in a static fluid, the position of the center of pressure is dependent on the depth of submersion and the radius of the disc.

Factors affecting the position of the center of pressure:
- Depth of submersion (h)
- Radius of the disc (r)

Relationship between the position of the center of pressure and h:
When the depth of submersion (h) is greater than the radius of the disc (r), the position of the center of pressure is directly proportional to the depth of submersion. This means that as the depth of submersion increases, the position of the center of pressure also increases.

Therefore, in the given scenario where h > r, the position of the center of pressure will be directly proportional to h. This relationship holds true for a circular disc submerged vertically in a static fluid.

In conclusion, the correct answer is option 'A': The position of the center of pressure will be directly proportional to the depth of submersion (h) when the depth of submersion is greater than the radius of the disc.
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A circular disc of radius 'r' is submerged vertically in a sta...
Pressure acting on the centre of the disc is directly proportional to height
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