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A cyclic heat engine does 50 kJ of work per cycle. If the efficiency of the heat engine is 75%, the heat rejected per cycle is
  • a)
    16.67 kJ    
  • b)
    33.30 kJ
  • c)
    37.50 kJ    
  • d)
    66.67 kJ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A cyclic heat engine does 50 kJ of work per cycle. If the efficiency o...
Carnot efficiency = Work done/Heat supplied(Q1)
0.75 = 50/ Q1
or, Q1 = 200/3
and, Work done = Q1– Q2
or, Q2 = 200/3-50 = 50/3 = 16.6kJ.
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Most Upvoted Answer
A cyclic heat engine does 50 kJ of work per cycle. If the efficiency o...
Calculation of Heat Rejected per Cycle in a Cyclic Heat Engine

Given data:
Work done per cycle (W) = 50 kJ
Efficiency of the heat engine (η) = 75%

We know that the efficiency of a heat engine is given by the formula:

η = (W/Q1) x 100%

Where Q1 is the heat absorbed per cycle.

Rearranging the above formula, we get:

Q1 = (W/η)

Substituting the given values, we get:

Q1 = (50/0.75)
Q1 = 66.67 kJ

Therefore, the heat absorbed per cycle (Q1) is 66.67 kJ.

We also know that in a cyclic heat engine, the heat absorbed per cycle (Q1) is equal to the sum of the heat rejected per cycle (Q2) and the work done per cycle (W). Mathematically,

Q1 = Q2 + W

Substituting the values of Q1 and W, we get:

66.67 = Q2 + 50

Solving for Q2, we get:

Q2 = 16.67 kJ

Therefore, the heat rejected per cycle (Q2) is 16.67 kJ, which is the correct answer.
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A cyclic heat engine does 50 kJ of work per cycle. If the efficiency o...
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A cyclic heat engine does 50 kJ of work per cycle. If the efficiency of the heat engine is 75%, the heat rejected per cycle isa)16.67 kJ b)33.30 kJc)37.50 kJ d)66.67 kJCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A cyclic heat engine does 50 kJ of work per cycle. If the efficiency of the heat engine is 75%, the heat rejected per cycle isa)16.67 kJ b)33.30 kJc)37.50 kJ d)66.67 kJCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cyclic heat engine does 50 kJ of work per cycle. If the efficiency of the heat engine is 75%, the heat rejected per cycle isa)16.67 kJ b)33.30 kJc)37.50 kJ d)66.67 kJCorrect answer is option 'A'. Can you explain this answer?.
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