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A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton is
- a)A circle of radius 0.2 m and time period p ×10-7s
- b)A circle of radius 0.1 m and time period 2p×10-7s
- c)A helix of radius 0.1 m and time period of 2p × 10-7 s
- d)A helix of radius of 0.2 m and time period 4p × 10-7s
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C i...
vx=vcosθ
vy=vsinθ
Since vy≠0, this component will be responsible for motion along the direction B( i.e y−axis).
The path will be helical and pitch will be constant.
Radius r of the circle perpendicular to the magnetic field B
r=mvcosθ/qB=1.6×10−27×(2×106×cos600)/ 1.6×10−19×0.1=0.1m
T=2πr/v=2×π×0.1/2×106×cos600 =2π×10−7secs
vy=vsinθ
Since vy≠0, this component will be responsible for motion along the direction B( i.e y−axis).
The path will be helical and pitch will be constant.
Radius r of the circle perpendicular to the magnetic field B
r=mvcosθ/qB=1.6×10−27×(2×106×cos600)/ 1.6×10−19×0.1=0.1m
T=2πr/v=2×π×0.1/2×106×cos600 =2π×10−7secs
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A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer?.
A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A proton of mass 1.67 × 10-27 kg and charge 1.6 × 10-19C is projected with a speed of 2 × 106 m/s at an angle of 60° to the x-axis. If a uniform magnetic field of 0.104 T is applied along the y-axis, the path of te proton isa)A circle of radius 0.2 m and time period p ×10-7sb)A circle of radius 0.1 m and time period 2p×10-7sc)A helix of radius 0.1 m and time period of 2p × 10-7 sd)A helix of radius of 0.2 m and time period 4p × 10-7sCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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