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Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution is
  • a)
    1.78 M
  • b)
    2.00 M
  • c)
    2.05
  • d)
    2.22 M 
Correct answer is option 'C'. Can you explain this answer?
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Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solut...
To find the molarity of the solution, we need to determine the number of moles of urea and the volume of the solution.

1. Calculate the number of moles of urea:
Given that the molecular weight of urea is 60 g/mol and the mass of urea dissolved is 120 g, we can calculate the number of moles using the formula:

Number of moles = Mass of substance / Molecular weight
Number of moles of urea = 120 g / 60 g/mol
Number of moles of urea = 2 mol

2. Calculate the volume of the solution:
The density of the solution is given as 1.15 g/mL, and the mass of the solution is 1000 g. We can calculate the volume of the solution using the formula:

Volume of solution = Mass of solution / Density
Volume of solution = 1000 g / 1.15 g/mL
Volume of solution = 869.57 mL

3. Convert the volume of the solution to liters:
1 L = 1000 mL
Volume of solution = 869.57 mL / 1000 mL/L
Volume of solution = 0.86957 L

4. Calculate the molarity of the solution:
Molarity = Number of moles / Volume of solution
Molarity = 2 mol / 0.86957 L
Molarity ≈ 2.05 M

Therefore, the molarity of the solution is approximately 2.05 M, which matches option C.
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Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solut...
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Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution isa)1.78 Mb)2.00 Mc)2.05d)2.22 MCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution isa)1.78 Mb)2.00 Mc)2.05d)2.22 MCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Dissolving 120 g of urea (mol. Wt. 60) in 1000 g of water gave a solution of density 1.15 g/mL. The molarity of the solution isa)1.78 Mb)2.00 Mc)2.05d)2.22 MCorrect answer is option 'C'. Can you explain this answer?.
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