Class 11 Exam > Class 11 Questions > An automobile travelling with a speed of 60 k...
Start Learning for Free
An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]
- a)20 m
- b)40 m
- c)60m
- d)80 m
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An automobile travelling with a speed of 60 km/h, can brake to stop wi...
The initial speed of the car in 1st case = 60kmph = 50/3 m/s
Final speed = 0
Let the deceleration be a
We have
(0)^2 - (50/3)^2 = 2ax(20)
=>a = -(50/3)^2/40 = - 6.94 ms^-2 (approx)
Considering the acceleration to be same in both case
The initial speed at the second case = 120kmph=100/3 m/s
Let the distance be x
Final speed = 0
We have
v^2-u^2 =2ax
=>0^2 – (100/3)^2 =2x (-6.94)x
=>x = 80 m
Most Upvoted Answer
An automobile travelling with a speed of 60 km/h, can brake to stop wi...
V2-u2=2as kinematics equation,v=0,u2= 2as s directly proportional to u2
Free Test
FREE
| Start Free Test |
Community Answer
An automobile travelling with a speed of 60 km/h, can brake to stop wi...
Given:
Speed of the car = 60 km/h
Stopping distance at this speed = 20 m
To find:
Stopping distance when the car is going twice as fast, i.e. 120 km/h
Solution:
1. Conversion of speed:
We need to convert the speed from km/h to m/s in order to use it in the formulas.
Given speed = 60 km/h
To convert km/h to m/s, we use the conversion factor 1 km/h = 0.2778 m/s.
Therefore, the speed in m/s is calculated as:
60 km/h × 0.2778 m/s = 16.67 m/s
2. Calculation of initial velocity:
In order to calculate the stopping distance when the car is going twice as fast, we need to calculate the initial velocity at this speed.
Given speed = 120 km/h
To convert km/h to m/s, we use the conversion factor 1 km/h = 0.2778 m/s.
Therefore, the initial velocity in m/s is calculated as:
120 km/h × 0.2778 m/s = 33.33 m/s
3. Calculation of stopping distance:
We can use the formula for stopping distance, which is given by:
Stopping distance = (Initial velocity^2 - Final velocity^2) / (2 × Acceleration)
The final velocity is 0 m/s since the car comes to a stop.
Using the formula and the given values, we can calculate the stopping distance when the car is going twice as fast:
Stopping distance = (33.33^2 - 0^2) / (2 × Acceleration)
We can see that the stopping distance is directly proportional to the square of the initial velocity. Therefore, when the initial velocity is doubled, the stopping distance will be four times the original stopping distance.
Hence, the stopping distance when the car is going twice as fast, i.e. 120 km/h, will be 4 times the original stopping distance.
Original stopping distance = 20 m
Stopping distance at 120 km/h = 4 × 20 m = 80 m
Therefore, the correct answer is option D) 80 m.
Speed of the car = 60 km/h
Stopping distance at this speed = 20 m
To find:
Stopping distance when the car is going twice as fast, i.e. 120 km/h
Solution:
1. Conversion of speed:
We need to convert the speed from km/h to m/s in order to use it in the formulas.
Given speed = 60 km/h
To convert km/h to m/s, we use the conversion factor 1 km/h = 0.2778 m/s.
Therefore, the speed in m/s is calculated as:
60 km/h × 0.2778 m/s = 16.67 m/s
2. Calculation of initial velocity:
In order to calculate the stopping distance when the car is going twice as fast, we need to calculate the initial velocity at this speed.
Given speed = 120 km/h
To convert km/h to m/s, we use the conversion factor 1 km/h = 0.2778 m/s.
Therefore, the initial velocity in m/s is calculated as:
120 km/h × 0.2778 m/s = 33.33 m/s
3. Calculation of stopping distance:
We can use the formula for stopping distance, which is given by:
Stopping distance = (Initial velocity^2 - Final velocity^2) / (2 × Acceleration)
The final velocity is 0 m/s since the car comes to a stop.
Using the formula and the given values, we can calculate the stopping distance when the car is going twice as fast:
Stopping distance = (33.33^2 - 0^2) / (2 × Acceleration)
We can see that the stopping distance is directly proportional to the square of the initial velocity. Therefore, when the initial velocity is doubled, the stopping distance will be four times the original stopping distance.
Hence, the stopping distance when the car is going twice as fast, i.e. 120 km/h, will be 4 times the original stopping distance.
Original stopping distance = 20 m
Stopping distance at 120 km/h = 4 × 20 m = 80 m
Therefore, the correct answer is option D) 80 m.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Question Description
An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer?.
An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer?.
Solutions for An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be [AIEEE 2004]a)20 mb)40 mc)60md)80 mCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily