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If the sum of square of diffrences of rank is 50 and numbers of items is 8 then what is the value of rank correlation coefficient?
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If the sum of square of diffrences of rank is 50 and numbers of items ...
Calculation of Rank Correlation Coefficient


Given Data:


  • Sum of square of differences of rank = 50

  • Number of items = 8



Formula for Rank Correlation Coefficient:

Spearman's Rank Correlation Coefficient formula is:

r = 1 - (6Σd²)/(n(n²-1))

Where,


  • r = Rank Correlation Coefficient

  • d = Difference between paired ranks

  • n = Number of pairs



Calculation:

Given that sum of square of differences of rank = 50 and number of items = 8

So, number of pairs = n(n-1)/2 = 8(8-1)/2 = 28

Now, we need to find the value of Σd²

Let's assume the paired ranks are (x1,y1), (x2,y2), (x3,y3),...,(x8,y8)


  • d₁ = x₁ - y₁

  • d₂ = x₂ - y₂

  • d₃ = x₃ - y₃

  • .

  • .

  • .

  • d₈ = x₈ - y₈


So, Σd² = d₁² + d₂² + d₃² + ... + d₈²

Now, we need to calculate each value of d using the given data.

From the given data, we don't have the actual values of paired ranks. Hence, we cannot calculate the value of r.

Therefore, the Rank Correlation Coefficient cannot be calculated without the actual values of paired ranks.
Community Answer
If the sum of square of diffrences of rank is 50 and numbers of items ...
A 0.59 b 0.40 c 0.36 d 0.63
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If the sum of square of diffrences of rank is 50 and numbers of items is 8 then what is the value of rank correlation coefficient?
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