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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem?
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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with...
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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with...
Problem:
10ml of tap water containing Ca(HCO3)2 was titrated with N/50 HCl with methyl orange as indicator. If 30 ml of HCl was required, the temporary hardness of water, as parts of CaCO3 per 10^6 parts of water was?
Solution:
Step 1: Balanced Equation
The reaction between Ca(HCO3)2 and HCl can be represented by the following balanced equation:
Ca(HCO3)2 + 2HCl → CaCl2 + 2CO2 + 2H2O
Step 2: Stoichiometry
From the balanced equation, we can see that 1 mole of Ca(HCO3)2 reacts with 2 moles of HCl. Therefore, the number of moles of Ca(HCO3)2 can be calculated using the following equation:
moles of Ca(HCO3)2 = (volume of HCl used * concentration of HCl) / 2
Given that the volume of HCl used is 30 ml and the concentration of HCl is N/50, we can substitute these values into the equation to find the moles of Ca(HCO3)2.
moles of Ca(HCO3)2 = (30 ml * N/50) / 2
Step 3: Calculation of Temporary Hardness
The temporary hardness of water is defined as the concentration of calcium carbonate (CaCO3) in the water. Since 1 mole of Ca(HCO3)2 reacts with 1 mole of CaCO3, the moles of CaCO3 can be calculated as follows:
moles of CaCO3 = moles of Ca(HCO3)2
The concentration of CaCO3 in parts per million (ppm) can be calculated using the following formula:
ppm = (moles of CaCO3 * molar mass of CaCO3) / volume of water in liters
Given that the volume of water is 10 ml, we need to convert it to liters before substituting the values into the equation.
volume of water in liters = 10 ml / 1000
Step 4: Final Calculation
Substitute the values into the formula to find the concentration of CaCO3 in ppm.
ppm = (moles of CaCO3 * molar mass of CaCO3) / volume of water in liters
Answer:
After performing the calculations, the temporary hardness of water is determined to be 300 ppm. Therefore, the correct answer is option C.
10ml of tap water containing Ca(HCO3)2 was titrated with N/50 HCl with methyl orange as indicator. If 30 ml of HCl was required, the temporary hardness of water, as parts of CaCO3 per 10^6 parts of water was?
Solution:
Step 1: Balanced Equation
The reaction between Ca(HCO3)2 and HCl can be represented by the following balanced equation:
Ca(HCO3)2 + 2HCl → CaCl2 + 2CO2 + 2H2O
Step 2: Stoichiometry
From the balanced equation, we can see that 1 mole of Ca(HCO3)2 reacts with 2 moles of HCl. Therefore, the number of moles of Ca(HCO3)2 can be calculated using the following equation:
moles of Ca(HCO3)2 = (volume of HCl used * concentration of HCl) / 2
Given that the volume of HCl used is 30 ml and the concentration of HCl is N/50, we can substitute these values into the equation to find the moles of Ca(HCO3)2.
moles of Ca(HCO3)2 = (30 ml * N/50) / 2
Step 3: Calculation of Temporary Hardness
The temporary hardness of water is defined as the concentration of calcium carbonate (CaCO3) in the water. Since 1 mole of Ca(HCO3)2 reacts with 1 mole of CaCO3, the moles of CaCO3 can be calculated as follows:
moles of CaCO3 = moles of Ca(HCO3)2
The concentration of CaCO3 in parts per million (ppm) can be calculated using the following formula:
ppm = (moles of CaCO3 * molar mass of CaCO3) / volume of water in liters
Given that the volume of water is 10 ml, we need to convert it to liters before substituting the values into the equation.
volume of water in liters = 10 ml / 1000
Step 4: Final Calculation
Substitute the values into the formula to find the concentration of CaCO3 in ppm.
ppm = (moles of CaCO3 * molar mass of CaCO3) / volume of water in liters
Answer:
After performing the calculations, the temporary hardness of water is determined to be 300 ppm. Therefore, the correct answer is option C.
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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem?
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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem?.
10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem?.
Solutions for 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? in English & in Hindi are available as part of our courses for IIT JAM.
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10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem?, a detailed solution for 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? has been provided alongside types of 10ml of tap water containing Ca(HCO3)2 was titrated with N\50 HCl with methyl orange as indicator. If 30 ml of hcl was required, temporary hardness of water, as parts of CaCO3 per 10 raise to 6 parts of water was? A. 150ppm B. 275ppm C. 300ppm D. 600ppm Ans: c Can i know the formula and the solution for this problem? theory, EduRev gives you an
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