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If y=|x| for x<0 and y=x for x ≥ 0, then 

  • a)
    y is discontinuous at x = 0 

  • b)

  • c)
    y is not defend at x = 0 

  • d)

Correct answer is option 'B'. Can you explain this answer?
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If y=|x| for x<0 and y=x for x ≥ 0, thena)y is discontinuous at ...

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If y=|x| for x<0 and y=x for x ≥ 0, thena)y is discontinuous at ...
I think the correct answer is (a), because y=|x| is always continuous. So the option b) and d) become false. Also the |x| function is defined at all real number,so the option c) is also false. The remaining is only option a) so that will be the correct answer.
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