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An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is?
Most Upvoted Answer
An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml...
Calculation of Volume of NaOH Required to Neutralize the Solution
Given:
Mass of oxalic acid dihydrate = 6.3g
Volume of solution = 250 ml
Concentration of NaOH = 0.1N
Volume of solution to be neutralized = 10 ml
Formula:
Moles of oxalic acid dihydrate = (mass of oxalic acid dihydrate) / (molar mass of oxalic acid dihydrate)
Moles of NaOH = (concentration of NaOH) x (volume of NaOH used in liters)
Moles of oxalic acid dihydrate = moles of NaOH (at equivalence point)
Calculation:
Molar mass of oxalic acid dihydrate = molar mass of oxalic acid + 2 x molar mass of water
Molar mass of oxalic acid dihydrate = (2 x 1) + (2 x 16) + 2 x [1 + (2 x 16)]
Molar mass of oxalic acid dihydrate = 126 g/mol
Moles of oxalic acid dihydrate = (6.3g) / (126 g/mol) = 0.05 mol
At equivalence point, moles of NaOH = moles of oxalic acid dihydrate
Therefore, moles of NaOH = 0.05 mol
Moles of NaOH = (concentration of NaOH) x (volume of NaOH used in liters)
Volume of NaOH used in liters = moles of NaOH / concentration of NaOH
Volume of NaOH used in liters = 0.05 mol / 0.1N = 0.5 L
Volume of NaOH used in 10 ml of solution = (0.5 L / 250 ml) x 10 ml = 0.02 ml
Therefore, the volume of NaOH required to completely neutralize 10 ml of this solution is 0.02 ml.
Community Answer
An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml...
Equivalent mass of C2H2O4.2H2O = 126/2 = 63 Normality of oxalic acid = 6.3/63 * 1000/250 = 0.4 N =>N1V1 = N2V2 N1 =>normality of oxalic acid V1 = volume of oxalic acid N2 =normality of sodium hydroxide V2 =volume of sodium hydroxide =>0.4 * 10 = 0.1 * V2 =>V2 = 40 ml.
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An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is?
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An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is?.
An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution of 6.3g oxalic acid dihydrate is made up to 250 ml. the volume of 0.1N NaOH req to completely neutralize 10 ml of this solution is?.
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