When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer?

Question

Answer

I also get the answer as 8, it is correct...

Answer

Milliequivalents of the acid taken = 4×2 =8. neutralization of 8 meq liberated 64 cal heat. So heat of neutralization is 64/8 = 8cal/meq.

Answer

Milliequivalents of the acid taken = 4×2 =8.
neutralization of 8 meq liberated 64 cal heat.
So the heat of neutralization is 64/8 = 8cal/meq.

Answer

Understanding Heat of Neutralization
The heat of neutralization is the amount of heat released when an acid reacts with a base to form water and a salt. In this case, we have a weak acid neutralized by sodium hydroxide.
Given Data
- Volume of weak acid solution = 4.0 mL
- Normality of weak acid solution = 2.0 N
- Heat released during neutralization = 64 cal
Calculating Milliequivalents of Acid
To find the heat of neutralization in cal/milliequivalent, we first calculate the number of milliequivalents of the weak acid:
- Normality (N) indicates equivalents per liter. Thus, 2.0 N means there are 2 equivalents in 1 L (1000 mL).
- For 4.0 mL of the acid solution:
- Milliequivalents = Normality x Volume (in mL)
- Milliequivalents of acid = 2.0 N x 4.0 mL = 8 milliequivalents
Calculating Heat of Neutralization
Now, we can find the heat of neutralization per milliequivalent:
- Heat of neutralization (cal/milliequivalent) = Total heat released / Milliequivalents of acid
- Heat of neutralization = 64 cal / 8 milliequivalents = 8 cal/milliequivalent
Conclusion
The heat of neutralization for this reaction is 8 cal/milliequivalent, indicating that for every milliequivalent of the weak acid neutralized, 8 calories of heat are released. This result aligns with typical values for neutralization reactions, reinforcing the concept of energy changes during acid-base reactions.

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