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When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?
Correct answer is '8'. Can you explain this answer?
Verified Answer
When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute ...
Milliequivalents of the acid taken = 4×2 =8.
neutralization of 8 meq liberated 64 cal heat.
So the heat of neutralization is 64/8 = 8cal/meq.
neutralization of 8 meq liberated 64 cal heat.
So the heat of neutralization is 64/8 = 8cal/meq.
Most Upvoted Answer
When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute ...
Milliequivalents of the acid taken = 4×2 =8.
neutralization of 8 meq liberated 64 cal heat.
So the heat of neutralization is 64/8 = 8cal/meq.
neutralization of 8 meq liberated 64 cal heat.
So the heat of neutralization is 64/8 = 8cal/meq.
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When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute ...
Understanding Heat of Neutralization
The heat of neutralization is the amount of heat released when an acid reacts with a base to form water and a salt. In this case, we have a weak acid neutralized by sodium hydroxide.
Given Data
- Volume of weak acid solution = 4.0 mL
- Normality of weak acid solution = 2.0 N
- Heat released during neutralization = 64 cal
Calculating Milliequivalents of Acid
To find the heat of neutralization in cal/milliequivalent, we first calculate the number of milliequivalents of the weak acid:
- Normality (N) indicates equivalents per liter. Thus, 2.0 N means there are 2 equivalents in 1 L (1000 mL).
- For 4.0 mL of the acid solution:
- Milliequivalents = Normality x Volume (in mL)
- Milliequivalents of acid = 2.0 N x 4.0 mL = 8 milliequivalents
Calculating Heat of Neutralization
Now, we can find the heat of neutralization per milliequivalent:
- Heat of neutralization (cal/milliequivalent) = Total heat released / Milliequivalents of acid
- Heat of neutralization = 64 cal / 8 milliequivalents = 8 cal/milliequivalent
Conclusion
The heat of neutralization for this reaction is 8 cal/milliequivalent, indicating that for every milliequivalent of the weak acid neutralized, 8 calories of heat are released. This result aligns with typical values for neutralization reactions, reinforcing the concept of energy changes during acid-base reactions.
The heat of neutralization is the amount of heat released when an acid reacts with a base to form water and a salt. In this case, we have a weak acid neutralized by sodium hydroxide.
Given Data
- Volume of weak acid solution = 4.0 mL
- Normality of weak acid solution = 2.0 N
- Heat released during neutralization = 64 cal
Calculating Milliequivalents of Acid
To find the heat of neutralization in cal/milliequivalent, we first calculate the number of milliequivalents of the weak acid:
- Normality (N) indicates equivalents per liter. Thus, 2.0 N means there are 2 equivalents in 1 L (1000 mL).
- For 4.0 mL of the acid solution:
- Milliequivalents = Normality x Volume (in mL)
- Milliequivalents of acid = 2.0 N x 4.0 mL = 8 milliequivalents
Calculating Heat of Neutralization
Now, we can find the heat of neutralization per milliequivalent:
- Heat of neutralization (cal/milliequivalent) = Total heat released / Milliequivalents of acid
- Heat of neutralization = 64 cal / 8 milliequivalents = 8 cal/milliequivalent
Conclusion
The heat of neutralization for this reaction is 8 cal/milliequivalent, indicating that for every milliequivalent of the weak acid neutralized, 8 calories of heat are released. This result aligns with typical values for neutralization reactions, reinforcing the concept of energy changes during acid-base reactions.
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When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer?.
When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 4.0 mL of 2.0 N solution of weak acid is neutralised by a dilute aqueous solution of sodium hydroxide, 64 cal of heat is liberated. What is the heat of neutralisation in cal/milliequivalent?Correct answer is '8'. Can you explain this answer?.
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