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If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus is
- a)1.223 x10-15 J
- b)-1.223x 10-15 J
- c)2.345 x10-15 J
- d)1.428 x10-15 J
Correct answer is option 'B'. Can you explain this answer?
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If the photon of the wavelength 150 pm strikes an atom and one of its ...
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If the photon of the wavelength 150 pm strikes an atom and one of its ...
Given:
Wavelength of photon, λ = 150 pm = 150 × 10^(-12) m
Velocity of ejected electron, v = 1.5 × 10^7 m/s
To find:
Binding energy of the electron to the nucleus
Explanation:
When a photon strikes an atom, it transfers its energy to one of the inner bound electrons. If this energy is sufficient, the electron can be ejected from the atom.
The energy of a photon is given by the equation:
E = hc/λ
Where:
E is the energy of the photon
h is the Planck's constant (6.626 × 10^(-34) J·s)
c is the speed of light (3.0 × 10^8 m/s)
λ is the wavelength of the photon
Calculating the energy of the photon:
E = (6.626 × 10^(-34) J·s × 3.0 × 10^8 m/s) / (150 × 10^(-12) m)
E = 3.313 × 10^(-19) J
This energy is transferred to the electron, causing it to gain kinetic energy. The kinetic energy of the ejected electron can be calculated using the equation:
KE = (1/2)mv^2
Where:
KE is the kinetic energy of the electron
m is the mass of the electron (9.109 × 10^(-31) kg)
v is the velocity of the electron
Calculating the kinetic energy of the electron:
KE = (1/2)(9.109 × 10^(-31) kg)(1.5 × 10^7 m/s)^2
KE = 1.367 × 10^(-15) J
The binding energy of the electron is equal to the difference between the energy of the photon and the kinetic energy gained by the electron:
Binding energy = E - KE
Binding energy = (3.313 × 10^(-19) J) - (1.367 × 10^(-15) J)
Binding energy = -1.036 × 10^(-15) J
Since binding energy is a positive quantity (the electron is bound to the nucleus), the answer is in option B: -1.223 × 10^(-15) J.
Wavelength of photon, λ = 150 pm = 150 × 10^(-12) m
Velocity of ejected electron, v = 1.5 × 10^7 m/s
To find:
Binding energy of the electron to the nucleus
Explanation:
When a photon strikes an atom, it transfers its energy to one of the inner bound electrons. If this energy is sufficient, the electron can be ejected from the atom.
The energy of a photon is given by the equation:
E = hc/λ
Where:
E is the energy of the photon
h is the Planck's constant (6.626 × 10^(-34) J·s)
c is the speed of light (3.0 × 10^8 m/s)
λ is the wavelength of the photon
Calculating the energy of the photon:
E = (6.626 × 10^(-34) J·s × 3.0 × 10^8 m/s) / (150 × 10^(-12) m)
E = 3.313 × 10^(-19) J
This energy is transferred to the electron, causing it to gain kinetic energy. The kinetic energy of the ejected electron can be calculated using the equation:
KE = (1/2)mv^2
Where:
KE is the kinetic energy of the electron
m is the mass of the electron (9.109 × 10^(-31) kg)
v is the velocity of the electron
Calculating the kinetic energy of the electron:
KE = (1/2)(9.109 × 10^(-31) kg)(1.5 × 10^7 m/s)^2
KE = 1.367 × 10^(-15) J
The binding energy of the electron is equal to the difference between the energy of the photon and the kinetic energy gained by the electron:
Binding energy = E - KE
Binding energy = (3.313 × 10^(-19) J) - (1.367 × 10^(-15) J)
Binding energy = -1.036 × 10^(-15) J
Since binding energy is a positive quantity (the electron is bound to the nucleus), the answer is in option B: -1.223 × 10^(-15) J.
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If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer?.
If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer?.
Solutions for If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 x 107 ms-1, then binding energy by which electron is bound to nucleus isa)1.223 x10-15 Jb)-1.223x 10-15 Jc)2.345 x10-15 Jd)1.428 x10-15 JCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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