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A man standing on the top of the tower 60m height throws a ball in the verticaly upward direction with a a velocity of 20m/s.how long will it take for the ball to pass by the man while moving in the downward direction?
1. 2 sec
2. 4 sec
3. 6 sec
4. 8 sec?
given answer is 4 sec?
1. 2 sec
2. 4 sec
3. 6 sec
4. 8 sec?
given answer is 4 sec?
Most Upvoted Answer
A man standing on the top of the tower 60m height throws a ball in the...
Solution
Initial Velocity
The initial velocity of the ball is given as 20m/s, in the upward direction.
Final Velocity
At the maximum height, the velocity of the ball becomes zero.
Acceleration
The acceleration acting on the ball is due to gravity and is equal to -9.8m/s².
Time Taken
Using the formula of motion, v = u + at, where
- v = final velocity = 0
- u = initial velocity = 20m/s
- a = acceleration = -9.8m/s²
- t = time taken
We get,
t = (v - u) / a
t = (0 - 20) / (-9.8)
t = 2 seconds
Total Time
The total time taken by the ball to pass by the man while moving in the downward direction is twice the time taken to reach the maximum height.
Total time taken = 2 x 2 seconds
Total time taken = 4 seconds
Answer
Therefore, the correct answer is option 2, 4 seconds.
Community Answer
A man standing on the top of the tower 60m height throws a ball in the...
Given, that balls is thrown vertically upward,
so,
u = 20 m/s
a = g = 10 m/s^2
velocity at the top of the tower, v = 0
using v = u + at, we get,
# 0 = 20 - (10 × t), due to gravity in opposite direction, a = -g
# -20 = -10t
# t = 20 /10
# t = 2 seconds
We know that, time of acent = time of decent, therefore, time of acent = time of decent = 2 seconds.
Therefore, the ball will pass at t = 4 seconds.
so,
u = 20 m/s
a = g = 10 m/s^2
velocity at the top of the tower, v = 0
using v = u + at, we get,
# 0 = 20 - (10 × t), due to gravity in opposite direction, a = -g
# -20 = -10t
# t = 20 /10
# t = 2 seconds
We know that, time of acent = time of decent, therefore, time of acent = time of decent = 2 seconds.
Therefore, the ball will pass at t = 4 seconds.
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A man standing on the top of the tower 60m height throws a ball in the verticaly upward direction with a a velocity of 20m/s.how long will it take for the ball to pass by the man while moving in the downward direction?1. 2 sec 2. 4 sec 3. 6 sec4. 8 sec?given answer is 4 sec?
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A man standing on the top of the tower 60m height throws a ball in the verticaly upward direction with a a velocity of 20m/s.how long will it take for the ball to pass by the man while moving in the downward direction?1. 2 sec 2. 4 sec 3. 6 sec4. 8 sec?given answer is 4 sec? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A man standing on the top of the tower 60m height throws a ball in the verticaly upward direction with a a velocity of 20m/s.how long will it take for the ball to pass by the man while moving in the downward direction?1. 2 sec 2. 4 sec 3. 6 sec4. 8 sec?given answer is 4 sec? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man standing on the top of the tower 60m height throws a ball in the verticaly upward direction with a a velocity of 20m/s.how long will it take for the ball to pass by the man while moving in the downward direction?1. 2 sec 2. 4 sec 3. 6 sec4. 8 sec?given answer is 4 sec?.
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