JEE Exam > JEE Questions > The radius of blade of fan is 0.3m. it is mak...
Start Learning for Free
The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b?
Most Upvoted Answer
The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceler...
Understanding the Problem
To find the acceleration of a particle at the tip of the fan blade, we need to calculate the centripetal acceleration. This acceleration can be determined using the formula:
Centripetal Acceleration (a) = ω² * r
Where:
- ω = angular velocity in radians per second
- r = radius of the blade
Step 1: Convert RPM to Radians per Second
- Given that the fan is rotating at 1200 RPM:
- 1 RPM = 2π radians / 60 seconds
- Therefore, 1200 RPM = 1200 * (2π / 60) = 40π radians/second
Step 2: Calculate Centripetal Acceleration
- Given the radius (r) of the blade is 0.3m:
- Substitute the values into the formula:
Centripetal Acceleration = (40π)² * 0.3
- Calculating this step-by-step:
- (40π)² = 1600π²
- Now, multiply by 0.3:
Centripetal Acceleration = 1600π² * 0.3 ≈ 4740 m/s²
Final Result
- The acceleration of the particle at the tip of the blade is approximately 4740 m/s².
Conclusion
- The correct option is indeed (b) 4740 m/s². This calculation shows the significant acceleration experienced at the tip of the fan blade due to its high rotational speed.
To find the acceleration of a particle at the tip of the fan blade, we need to calculate the centripetal acceleration. This acceleration can be determined using the formula:
Centripetal Acceleration (a) = ω² * r
Where:
- ω = angular velocity in radians per second
- r = radius of the blade
Step 1: Convert RPM to Radians per Second
- Given that the fan is rotating at 1200 RPM:
- 1 RPM = 2π radians / 60 seconds
- Therefore, 1200 RPM = 1200 * (2π / 60) = 40π radians/second
Step 2: Calculate Centripetal Acceleration
- Given the radius (r) of the blade is 0.3m:
- Substitute the values into the formula:
Centripetal Acceleration = (40π)² * 0.3
- Calculating this step-by-step:
- (40π)² = 1600π²
- Now, multiply by 0.3:
Centripetal Acceleration = 1600π² * 0.3 ≈ 4740 m/s²
Final Result
- The acceleration of the particle at the tip of the blade is approximately 4740 m/s².
Conclusion
- The correct option is indeed (b) 4740 m/s². This calculation shows the significant acceleration experienced at the tip of the fan blade due to its high rotational speed.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
Question Description
The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b?.
The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b?.
Solutions for The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? defined & explained in the simplest way possible. Besides giving the explanation of
The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b?, a detailed solution for The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? has been provided alongside types of The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? theory, EduRev gives you an
ample number of questions to practice The radius of blade of fan is 0.3m. it is making 1200 rpm. the acceleration of particle at the tip of balde is?? a)1600ms^-2. b)4740ms^-2 correct option is b? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup