A coin is tossed 6 times, in how many throws can 4 heads and 2 tails be obtained?a)24b)18c)15d)10Correct answer is option 'C'. Can you explain this answer?

Question

Answer

Whether we toss a coin 6 times or six coins one time the number of arrangement will remain same .

As to find number of ways we get 4 heads and 2 tails out of 6 times

Answer

Howw

Answer

Given that a coin is tossed 6 times
total possible combination =2^6=64
let A be the event of getting for head and two tails
C(6,4)*B(2,2)
=15*1
=15
therefore the right option is C
Hope it helps!!!

Answer

Analysis:

To solve this problem, we need to consider the number of ways we can arrange 4 heads and 2 tails in 6 tosses of a coin.

Solution:

To obtain 4 heads and 2 tails, we need to find the number of combinations that can be formed using 4H and 2T in 6 tosses.

Step 1: Finding the number of combinations

We can use the formula for combinations to calculate the number of ways we can arrange the heads and tails. The formula for combinations is given by:

C(n, r) = n! / (r! * (n-r)!)

Where n is the total number of items, r is the number of items chosen at a time, and ! denotes the factorial of a number.

In this case, we need to find C(6, 4) as we want to select 4 positions for heads out of 6 tosses. Using the formula, we can calculate:

C(6, 4) = 6! / (4! * (6-4)!)
= 6! / (4! * 2!)
= (6 * 5 * 4!) / (4! * 2)
= (6 * 5) / 2
= 15

So, there are 15 different combinations of 4 heads and 2 tails in 6 tosses.

Step 2: Finding the number of throws

Since each combination represents a different arrangement of heads and tails, we can say that each combination represents a unique throw. Therefore, the number of throws is equal to the number of combinations, which is 15.

Therefore, the correct answer is option C) 15.

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