The structure of the complexes [Cu(NH3)4](CIO4)2 and [Cu(NH3)4](CIO4) ...
With cu2+ NH3 behaves as strong field ligand and configuration is d9 so it is square palnnar..with cu+ it is d10 configuration so it is tetrahedral...Note we have to check square plannar only in d8 and d9 complaxes..some rule which decides square plannar complexes
The structure of the complexes [Cu(NH3)4](CIO4)2 and [Cu(NH3)4](CIO4) ...
Explanation:
Cu(NH3)4 is a complex ion which is tetrahedral in shape. It is formed when copper(II) ions react with ammonia in aqueous solution. The ammonia molecules act as ligands and surround the copper ion, forming four coordinate bonds with it.
[Cu(NH3)4]2+ + 2ClO4- → [Cu(NH3)4](ClO4)2
The structure of [Cu(NH3)4](ClO4)2 is square planar. In this structure, the copper ion is surrounded by four ammonia molecules in a square planar arrangement, with the two perchlorate ions located above and below the plane. The four nitrogen atoms of the ammonia molecules are arranged in a square with the copper ion at the center.
In solution, the complex ion is surrounded by water molecules, which replace some or all of the ammonia molecules. The structure of the complex ion in solution depends on the number of water molecules present and their arrangement around the copper ion.
Overall, the structure of [Cu(NH3)4](ClO4)2 is tetrahedral, but in solution, it takes on a square planar structure due to the presence of the perchlorate ions.
Thus, the correct answer is option A, square planar and tetrahedral.