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What is the value of a3 +b3 +c3,if (a+b+c)=0?
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What is the value of a3 +b3 +c3,if (a+b+c)=0?
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What is the value of a3 +b3 +c3,if (a+b+c)=0?
Given ,(a+b+c)= 0 then ,a+b=-c
cubing both side
(a+b)^3 =-(c)^3
=a^3+b^3+3ab(a+b)=-c^3
=a^3+b^3+3ab×-c = -c^3
=a^3+b^3-3abc = -c^3
=a^3+b^3+c^3 = 3abc(Ans).
Community Answer
What is the value of a3 +b3 +c3,if (a+b+c)=0?
First note that: 

a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc). 

By assumption a^3+b^3+c^3=3abc so the left hand side is 0. 

Therefore (a+b+c)(a^2+b^2+c^2-ab-ac-bc) = 0. So either a+b+c=0 or a^2+b^2+c^2-ab-ac-bc=0. 

Now suppose a^2+b^2+c^2 - ab-ac-bc =0. You can re-write this as: 

(1/2) ( (a-b)^2 + (b-c)^2 + (c-a)^2 )=0 

Therefore (a-b)^2 + (b-c)^2 + (c-a)^2 =0 so a=b=c. 

So either a+b+c=0 or a=b=c. (So if a,b,c are all distinct then a+b+c=0). 
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