Answer:

Understanding the Problem:
We are given that the mixture contains the same number of molecules as that of 14g of CO. We need to determine the correct combination of nitrogen (N2) and oxygen (O2) that will have the same number of molecules as 14g of carbon monoxide (CO).

Calculating the Number of Molecules:
To compare the number of molecules, we need to calculate the number of moles for the given mass of CO. We can use the formula:

Number of moles (n) = Mass (m) / Molar mass (M)

The molar mass of CO is calculated as follows:
M(C) = 12.01 g/mol (molar mass of carbon)
M(O) = 16.00 g/mol (molar mass of oxygen)

Molar mass of CO = M(C) + M(O) = 12.01 g/mol + 16.00 g/mol = 28.01 g/mol

Using the given mass of 14g, we can calculate the number of moles of CO:
n(CO) = 14g / 28.01 g/mol = 0.4999 mol (approximately)

Since the mixture contains the same number of molecules as that of 14g of CO, the number of moles of the mixture should also be 0.4999 mol.

Options:
A) 14g of nitrogen + 16g of oxygen
B) 7g of nitrogen + 16g of oxygen
C) 14g of nitrogen + 8g of oxygen
D) 7g of nitrogen + 8g of oxygen

Calculating the Number of Moles for Each Option:
To determine the correct combination, we need to calculate the number of moles for each option and check if any combination gives us approximately 0.4999 mol.

Option A:
M(N) = 14.01 g/mol (molar mass of nitrogen)
M(O) = 16.00 g/mol (molar mass of oxygen)

Number of moles of nitrogen = 14g / 14.01 g/mol = 0.9993 mol (approximately)
Number of moles of oxygen = 16g / 16.00 g/mol = 1.0000 mol (approximately)

Total number of moles = 0.9993 mol + 1.0000 mol = 1.9993 mol (approximately)

Option B:
Number of moles of nitrogen = 7g / 14.01 g/mol = 0.4996 mol (approximately)
Number of moles of oxygen = 16g / 16.00 g/mol = 1.0000 mol (approximately)

Total number of moles = 0.4996 mol + 1.0000 mol = 1.4996 mol (approximately)

Option C:
Number of moles of nitrogen = 14g / 14.01 g/mol = 0.9993 mol (approximately)
Number of moles of oxygen = 8g / 16.00 g/mol = 0.5000 mol (approximately)

Total number of moles = 0.9993 mol + 0.5000 mol = 1.4993 mol (approximately)

Option D:
Number of moles of