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100 ml of 2M HCL solution completely neutralized by 10 grams of metal carbonate then Equivalent weight of the metal is?
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100 ml of 2M HCL solution completely neutralized by 10 grams of metal ...
For HCl 
Molarity = Normality

Gram equivalents of HCl = Normality x Volume in litres
= 2 N x 100 x 10^-3 L
= 0.2 eq

For complete neutralisation
Gram equivalents of HCl = Gram equivalents of metal carbonate

Equivalent weight of metal = Weight of metal / Gram equivalents of metal
= 10 g / 0.2 eq
= 50 g/eq

∴ Equivalent weight of metal is 50 g/eq
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100 ml of 2M HCL solution completely neutralized by 10 grams of metal ...
Neutralization Reaction:

In a neutralization reaction, an acid and a base react to form a salt and water. The reaction can be represented as follows:

Acid + Base → Salt + Water

In this case, the acid is hydrochloric acid (HCl) and the base is a metal carbonate. When HCl reacts with a metal carbonate, it produces a salt (metal chloride) and water.

Given Information:

- Volume of HCl solution = 100 ml
- Concentration of HCl solution = 2M
- Mass of metal carbonate used = 10 grams

Calculating Moles of HCl:

To find the equivalent weight of the metal, we first need to calculate the moles of HCl used in the reaction.

Moles of HCl = Concentration of HCl × Volume of HCl solution
= 2M × 0.1 L (since 100 ml = 0.1 L)
= 0.2 moles

Calculating Moles of Metal Carbonate:

The balanced chemical equation for the reaction between HCl and a metal carbonate will help us determine the stoichiometry of the reaction.

The balanced chemical equation is:
2 HCl + MCO3 → MCl2 + H2O + CO2

From the equation, we can see that 2 moles of HCl react with 1 mole of metal carbonate.

Moles of metal carbonate = 0.2 moles (since 2 moles of HCl react with 1 mole of metal carbonate)

Calculating Equivalent Weight:

The equivalent weight of a substance is the weight of the substance that reacts with or is equivalent to one mole of hydrogen ions (H+).

Equivalent weight = Mass of metal carbonate used / Moles of metal carbonate

In this case, the mass of metal carbonate used is given as 10 grams, and the moles of metal carbonate is calculated to be 0.2 moles.

Equivalent weight = 10 grams / 0.2 moles
= 50 grams/mol

Therefore, the equivalent weight of the metal is 50 grams/mol.
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100 ml of 2M HCL solution completely neutralized by 10 grams of metal carbonate then Equivalent weight of the metal is?
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