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How much heat energy a petrol engine would require to do 20 kWh of work? Its adiabatic compression ratio is 9 and γ= 1.5.

  • a)
    10.7 J

  • b)
    30 J

  • c)
    1.07 X10J

  • d)
    180 J

Correct answer is option 'B'. Can you explain this answer?
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The fuel's calorific value is 44 MJ/kg.

To calculate the amount of heat energy required, we can use the equation:

Heat energy = Work done / Efficiency

First, we need to calculate the efficiency of the engine. We can use the formula:

Efficiency = 1 - (1 / compression ratio)^((gamma - 1) / gamma)

where gamma is the specific heat ratio of the engine. For a petrol engine, gamma is typically around 1.4.

So, plugging in the values, we get:

Efficiency = 1 - (1 / 9)^(0.4) = 0.576

Now we can calculate the amount of heat energy required:

Heat energy = 20 kWh / 0.576 = 34.72 kWh

To convert this to joules, we multiply by 3,600,000 (1 kWh = 3,600,000 J):

Heat energy = 125,001,600 J

Finally, we can calculate the mass of fuel required using its calorific value:

Mass of fuel = Heat energy / Calorific value

Mass of fuel = 125,001,600 J / 44 MJ/kg = 2.84 kg

Therefore, a petrol engine with an adiabatic compression ratio of 9 would require approximately 2.84 kg of fuel to do 20 kWh of work.
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