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The relationship between osmotic pressure at 273 K when 10 g glucose (P1) 10 g urea (P2) and 10 g sucrose (P3) are dissolved in 250 ml of water is -
  • a)
    P> P> P3
  • b)
    P> P> P2 
  • c)
    P> P> P3
  • d)
    P> P> P1
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The relationship between osmotic pressure at 273 K when 10 g glucose (...
As number of moles is maximum in case urea > glucose > sucrose
π = CRT
It depends on number of moles so osmotic pressure
P2 > P1 > P3
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The relationship between osmotic pressure at 273 K when 10 g glucose (...
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The relationship between osmotic pressure at 273 K when 10 g glucose (...

Explanation:

Given Data:
- Osmotic pressure at 273 K when 10 g glucose (P1), 10 g urea (P2), and 10 g sucrose (P3) are dissolved in 250 ml of water.

Understanding Osmotic Pressure:
- Osmotic pressure is the pressure required to prevent the flow of solvent across a semipermeable membrane.

Calculating Osmotic Pressure:
- Osmotic pressure is directly proportional to the concentration of the solute particles.
- Glucose, urea, and sucrose all will dissociate into one particle each in solution, so the concentration of solute particles is the same for all three substances.

Comparing Osmotic Pressure:
- When comparing P1, P2, and P3, the order of osmotic pressure will depend only on the nature of the solute particles and not on their specific identity.
- Therefore, the relationship between osmotic pressure for P1, P2, and P3 will be based on the order in which the solutes are presented.

Conclusion:
- The correct relationship between osmotic pressure at 273 K for 10 g glucose (P1), 10 g urea (P2), and 10 g sucrose (P3) dissolved in 250 ml of water is P2 (urea) P1 (glucose) P3 (sucrose).
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Question Description
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