Sum of two numbers is 95. If one exceeds the other by 15, find the num...
Let the number be x.
So, the other number is (x + 15).
(x + 15) + x = 95
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 40
So, the numbers are 40 and 55.
Sum of two numbers is 95. If one exceeds the other by 15, find the num...
Problem:
The problem states that the sum of two numbers is 95. If one number exceeds the other by 15, we need to find the two numbers.
Solution:
Let's assume the smaller number is x.
According to the given condition, the larger number is x + 15.
Equation 1:
The sum of the two numbers is 95.
x + (x + 15) = 95
Simplify:
2x + 15 = 95
Subtract 15 from both sides:
2x = 80
Divide both sides by 2:
x = 40
Answer:
The smaller number is 40.
The larger number is x + 15 = 40 + 15 = 55.
So, the two numbers are 40 and 55.
Explanation:
To solve this problem, we need to set up an equation based on the given information and then solve for the unknowns.
In this case, we are given that the sum of the two numbers is 95. We are also given that one number exceeds the other by 15.
To represent this information mathematically, we can let one number be x and the other number be x + 15.
We can then set up the equation x + (x + 15) = 95 to represent the sum of the two numbers.
Simplifying this equation, we get 2x + 15 = 95.
Subtracting 15 from both sides, we get 2x = 80.
Dividing both sides by 2, we find that x = 40.
Therefore, the smaller number is 40.
To find the larger number, we substitute the value of x back into the expression x + 15.
So, the larger number is 40 + 15 = 55.
Therefore, the two numbers are 40 and 55.