The number is :-a)Rationalb)Irrationalc)Bothd)Cant sayCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

If this number is rationalised then 3-√3×3-√3/3+√3×3-√3
=(3-√3)^2/3^2+√3²
=9+3-6√3/6
=12-6√3/6
=2-√3 this is an irrational number.

Answer

If this number is rationalised then 3-√3×3-√3/3+√3×3-√3
=(3-√3)^2/3^2+√3^2
=9+3-6√3/6
=12-6√3/6
=2-√3 this is an irrational number.

Answer

It is a irrational number only f it is in this form while on determine its denominator we will found a real number.9+3-6√3/6

Answer

Answer

First rationaize the denominator(3+√3)(3-√3).    (a+b)(a-b)=a^2-,b^2so it is equal to (3)^2-(√3)^2=9-3=6now as we multiplied the denominator by 3-√3 we will multiply the numerator too!!(3-√3)(3-√3). (a-b)^2=a^2+b^2-2ab=(3)^2+(√3)^2-(2×3×√3)9+3-6√312-6√3now substitute the numerator and the denominator..=12-6√3/6=2-√3 it I irrational

Answer

Because The answer become Zero hence it is Irrational number

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