The sum of the series 3 ½ + 7 + 10 &fr...

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The sum of the series 3 ½ + 7 + 10 ½ + 14 + …. To 17 terms is
• a)
530
• b)
535
• c)
535 ½
• d)
none of these

Here asked sum of 17th term, now we will use the formula is
= n/2 [ 2a + ( n-1)* d ]
= 17 /2 [ 2*(3 1/2) + (17 - 1 ) ( 3 1/2) ]
= 8.5 [ 7 + 16 ( 3 1/2 )
= 8.5 [ 7 + 56 ]
= 8.5 [ 63]
=535.5

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The sum of the series 3 ½ + 7 + 10 ½ + 14 + …. To 17 terms isa)530b)535c)535 ½d)none of theseCorrect answer is option 'C'. Can you explain this answer?
N=17, a=3.1/2= 3.5, d= 3.1/2= 3.5
= n/2 [ 2a + ( n-1)* d ]

= 17 /2 [ 2*(3 .5) + (17 - 1 ) ( 3 .5) ]

= 8.5 [ 7 + 16 ( 3 .5 )

= 8.5 [ 7 + 56 ]

= 8.5 [ 63]

=535.5

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