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To balance the oxygen atom in the given reaction in acidic medium
Cr2O72- (aq) → Cr3+(aq) we
Cr2O72- (aq) → Cr3+(aq) we
- a)Add water (H2O) on right side
- b)Add water (H2O) on left side
- c)Add O on right side
- d)Add O on left side
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
To balance the oxygen atom in the given reaction in acidic mediumCr2O7...
As it is given that this reaction is in acidic medium, that means we have H+ on reactant side so to balance Oxygen we have to add water on product side instead of adding just Oxygen.
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To balance the oxygen atom in the given reaction in acidic mediumCr2O7...
Balancing the Oxygen Atom in the Given Reaction in Acidic Medium: Cr2O72-(aq) + Cr3(aq)
To balance the oxygen atoms in the given reaction in acidic medium, we need to follow a step-by-step process. In this case, the correct answer is option 'A', which suggests adding water (H2O) on the right side of the reaction.
Explanation:
Step 1: Write the Unbalanced Equation
Cr2O72-(aq) + Cr3(aq) -->
Step 2: Identify the Oxygen Atoms
The unbalanced equation contains a total of 14 oxygen atoms. To balance the equation, the number of oxygen atoms on both sides of the equation should be equal.
Step 3: Add Water (H2O) Molecules
To balance the oxygen atoms, we can add water (H2O) molecules to the equation. Since this is an acidic medium, we will add water molecules on the right side of the equation.
Step 4: Determine the Number of Water Molecules to Add
To balance the oxygen atoms, we need to add 7 water (H2O) molecules on the right side of the equation. This will provide a total of 14 oxygen atoms, balancing the equation.
Step 5: Write the Balanced Equation
Cr2O72-(aq) + Cr3(aq) + 7H2O(l) -->
Step 6: Balance the Hydrogen Atoms
After adding water molecules, we need to balance the hydrogen atoms. In this case, we have 14 hydrogen atoms on the right side of the equation. To balance the hydrogen atoms, we can add 14 H+ ions on the left side of the equation.
Step 7: Final Balanced Equation
Cr2O72-(aq) + 14H+ + Cr3(aq) + 7H2O(l)
Summary:
To balance the oxygen atoms in the given reaction in acidic medium, we added water (H2O) molecules on the right side of the equation. This balanced the equation and resulted in the final balanced equation: Cr2O72-(aq) + 14H+ + Cr3(aq) + 7H2O(l).
To balance the oxygen atoms in the given reaction in acidic medium, we need to follow a step-by-step process. In this case, the correct answer is option 'A', which suggests adding water (H2O) on the right side of the reaction.
Explanation:
Step 1: Write the Unbalanced Equation
Cr2O72-(aq) + Cr3(aq) -->
Step 2: Identify the Oxygen Atoms
The unbalanced equation contains a total of 14 oxygen atoms. To balance the equation, the number of oxygen atoms on both sides of the equation should be equal.
Step 3: Add Water (H2O) Molecules
To balance the oxygen atoms, we can add water (H2O) molecules to the equation. Since this is an acidic medium, we will add water molecules on the right side of the equation.
Step 4: Determine the Number of Water Molecules to Add
To balance the oxygen atoms, we need to add 7 water (H2O) molecules on the right side of the equation. This will provide a total of 14 oxygen atoms, balancing the equation.
Step 5: Write the Balanced Equation
Cr2O72-(aq) + Cr3(aq) + 7H2O(l) -->
Step 6: Balance the Hydrogen Atoms
After adding water molecules, we need to balance the hydrogen atoms. In this case, we have 14 hydrogen atoms on the right side of the equation. To balance the hydrogen atoms, we can add 14 H+ ions on the left side of the equation.
Step 7: Final Balanced Equation
Cr2O72-(aq) + 14H+ + Cr3(aq) + 7H2O(l)
Summary:
To balance the oxygen atoms in the given reaction in acidic medium, we added water (H2O) molecules on the right side of the equation. This balanced the equation and resulted in the final balanced equation: Cr2O72-(aq) + 14H+ + Cr3(aq) + 7H2O(l).
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To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer?.
To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer?.
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To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of To balance the oxygen atom in the given reaction in acidic mediumCr2O72-(aq) → Cr3+(aq) wea)Add water (H2O) on right sideb)Add water (H2O) on left sidec)Add O on right sided)Add O on left sideCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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