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If points corresponding to the complex numbers z1, z2, z3 and z4 are the vertices of a rhombus, taken in order, then for a non-zero real number k
  • a)
    z1 – z3 = i k( z2 –z4)
  • b)
    z1 – z2 = i k( z3 –z4)
  • c)
    z1 + z3 = k( z2 +z4)
  • d)
    z1 + z2 = k( z3 +z4)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If points corresponding to the complex numbers z1, z2, z3and z4are the...
AC = z3 = z1 eiπ
= z1 (cosπ + i sinπ)
= z3 = z1(-1 + i(0))
= z3 = -z1
AC = z1 - z3
BC = z2 - z4
(z1 - z3)/(z2 - z4) = k
(z1 - z3) = eiπ/2(z2 - z4)
(z1 - z3) k(cosπ/2 + sinπ/2) (z2 - z4)
z1 - z3 = ki(z2 - z4)
z1 - z3 = ik(z2 - z4)
 
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Most Upvoted Answer
If points corresponding to the complex numbers z1, z2, z3and z4are the...
We know that the opposite sides of a rhombus are parallel and equal in length. Therefore,
|z2 - z1| = |z4 - z3| (Opposite sides)
Also, the diagonals of a rhombus bisect each other at right angles. Therefore,
(z2 + z1)/2 + (z4 + z3)/2 = 2(z2 + z1 + z4 + z3)/4 = 0 (Diagonals bisect each other)
Simplifying the above equation, we get
z2 + z1 + z4 + z3 = 0
Now, let's consider the given expression k(z1 - z2)(z3 - z4).
Expanding this expression, we get
k(z1z3 - z1z4 - z2z3 + z2z4)
We can express z4 as z3 + (z2 - z1) (since z1z4 is parallel and equal to z2z3)
Substituting this value of z4 in the above expression, we get
k(z1z3 - z1(z3 + z2 - z1) - z2z3 + z2(z3 + z2 - z1))
Simplifying the above expression, we get
k(z1z2 - z1z3 - z2z3 + z2z3) = k(z1z2 - z1z3 - z2z3)
Now, we can express z1 as z2 + (z2 - z3) (since z1z2 is parallel and equal to z3z4)
Substituting this value of z1 in the above expression, we get
k((z2 + (z2 - z3))z2 - (z2 + (z2 - z3))z3 - z2z3) = k(z2^2 - z2z3 + z2^2 - z3z2 - z2z3) = k(2z2^2 - 2z2z3 - z3z2)
Now, we can use the fact that z2 + z1 + z4 + z3 = 0 to simplify the above expression. Substituting z4 as z3 + (z2 - z1) and rearranging the terms, we get
2(z2 - z1)(z3 - z2) = z3z2 - z2^2
Substituting this value in the above expression, we get
k(2z2^2 - 2z2z3 - (z3z2 - z2^2)) = k(z2^2 - 2z2z3 + z3^2)
Now, we can express z4 as z3 + (z1 - z2) (since z1z4 is parallel and equal to z2z3)
Substituting this value of z4 in the above expression, we get
k(z1z3 - z1(z3 + z1 - z2) - z2z3 + z2(z3 + z1 - z2))
Simplifying the above expression, we get
k(z1z2 - z2z3 - z1z2 + z1z3) = k(z1z3 -
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Community Answer
If points corresponding to the complex numbers z1, z2, z3and z4are the...
Option a is correct answer
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If points corresponding to the complex numbers z1, z2, z3and z4are the vertices of a rhombus, taken in order, then for a non-zero real number ka)z1– z3= i k( z2–z4)b)z1– z2= i k( z3–z4)c)z1+ z3= k( z2+z4)d)z1+ z2= k( z3+z4)Correct answer is option 'A'. Can you explain this answer?
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