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A ball whose kinetic energy is E, is projected at an angle of 45° to the horizontal. The kinetic energy of the ball at the highest point of its flight will be
[AIEEE 2002]
- a)E
- b)
- c)
- d)zero
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A ball whose kinetic energy is E, is projected at an angle of 45°...
At the highest point of its flight, the vertical component of velocity is zero and the only horizontal component is left which is ux = u cosθ
Given θ = 450
Given θ = 450
Most Upvoted Answer
A ball whose kinetic energy is E, is projected at an angle of 45°...
This is bcoz highest is the middle point of the trajectory so the kinetic energy will be the half of the energy at starting.
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Community Answer
A ball whose kinetic energy is E, is projected at an angle of 45°...
At the highest point of its flight, the vertical component of velocity is zero and the only horizontal component is left which is ux = u cosθ
Given θ = 450
Given θ = 450
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A ball whose kinetic energy is E, is projected at an angle of 45° to the horizontal. The kinetic energy of the ball at the highest point of its flight will be [AIEEE 2002] a)Eb)c)d)zeroCorrect answer is option 'C'. Can you explain this answer?
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