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Calculate the rate constants involved in the dissociation of NH4OH , vis., 
from the following data : A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5 mol dm–3. The observed relaxation time is 0.109 μs and xe = 4.1 × 10–4 mol dm–3. (in 1010 dm3 mol–1 s–1
    Correct answer is between '1.0,1.5'. Can you explain this answer?
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    Calculate the rate constants involved in the dissociation of NH4OH , vis.,from the following data: A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5mol dm–3. The observed relaxation time is 0.109μs and xe= 4.1 × 10–4mol dm–3. (in 1010dm3mol–1s–1)Correct answer is between '1.0,1.5'. Can you explain this answer?
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    Calculate the rate constants involved in the dissociation of NH4OH , vis.,from the following data: A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5mol dm–3. The observed relaxation time is 0.109μs and xe= 4.1 × 10–4mol dm–3. (in 1010dm3mol–1s–1)Correct answer is between '1.0,1.5'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Calculate the rate constants involved in the dissociation of NH4OH , vis.,from the following data: A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5mol dm–3. The observed relaxation time is 0.109μs and xe= 4.1 × 10–4mol dm–3. (in 1010dm3mol–1s–1)Correct answer is between '1.0,1.5'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the rate constants involved in the dissociation of NH4OH , vis.,from the following data: A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5mol dm–3. The observed relaxation time is 0.109μs and xe= 4.1 × 10–4mol dm–3. (in 1010dm3mol–1s–1)Correct answer is between '1.0,1.5'. Can you explain this answer?.
    Solutions for Calculate the rate constants involved in the dissociation of NH4OH , vis.,from the following data: A 0.01 molar solution of NH4OH is subjected to a sudden temperature jump terminating at 25°C, at which temperature, the equilibrium constant is 1.8 × 10–5mol dm–3. The observed relaxation time is 0.109μs and xe= 4.1 × 10–4mol dm–3. (in 1010dm3mol–1s–1)Correct answer is between '1.0,1.5'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
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