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In a box of 10 electric bulbs, two are defective. Two bulbs are selected at random one after the other from the box. The first bulb is put back in the box before making the second selection. The probability that both the bulbs are not defective is:​
  • a)
    8/25
  • b)
    4/5
  • c)
    16/25
  • d)
    9/25
Correct answer is option 'C'. Can you explain this answer?
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Problem:
In a box of 10 electric bulbs, two are defective. Two bulbs are selected at random one after the other from the box. The first bulb is put back in the box before making the second selection. The probability that both the bulbs are not defective is:

a) 8/25
b) 4/5
c) 16/25
d) 9/25

Solution:
To solve this problem, we need to find the probability that both bulbs selected are not defective. Let's break down the problem step by step:

Step 1: Finding the probability of selecting a non-defective bulb on the first draw:
- Out of the 10 bulbs, 2 are defective. So, the probability of selecting a non-defective bulb on the first draw is 8/10, which can be simplified as 4/5.

Step 2: Finding the probability of selecting a non-defective bulb on the second draw:
- Since the first bulb is put back into the box before the second draw, the total number of bulbs remains the same (10). Therefore, the probability of selecting a non-defective bulb on the second draw is also 8/10 or 4/5.

Step 3: Finding the probability of both bulbs being non-defective:
- To find the probability of multiple independent events occurring, we multiply their individual probabilities. So, the probability of both bulbs being non-defective is (4/5) * (4/5) = 16/25.

Therefore, the probability that both bulbs selected are not defective is 16/25, which corresponds to option (c).
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