Three coins are tossed. If at least two coins show head, the probabili...
Subset={HHH , HHT,HTH,HTT,THH,THT,TTH,TTT}
P(at least two head) = 4/8 = ½
Getting(one tail) = {HHT, HTH, THH}
= 3/8
Therefore, P(one tail) = (⅜) / (½)
= ¾
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Three coins are tossed. If at least two coins show head, the probabili...
Sample space = HHH, HHT, HTH, THH, TTH, THT, HTT, TTTGetting atleast two heads(F) = HHH, HHT, HTH, THHProbability of getting atleast two heads(F) = 4/8 =1/2Getting one tail (E) = HHT, HTH, THHE intersection F = HHT, HTH, THHP(E intersection F) = 3/8Required probability = P(E intersection F) / P(F) = 3/8 ÷ 1/2 =3/4
Three coins are tossed. If at least two coins show head, the probabili...
Subset={HHH , HHT,HTH,HTT,THH,THT,TTH,TTT}
P(at least two head and one tail)=6/8=3/4