Calculation of Percentage of Nitrogen

Given:
Mass of substance = 0.295 g
Volume of (N/10)H2SO4 = 50 mL

To calculate the percentage of nitrogen in the substance, we need to determine the number of moles of nitrogen and then find its percentage in the given mass.

Step 1: Calculate the number of moles of H2SO4

The volume of (N/10)H2SO4 is given as 50 mL. Since the concentration is expressed as N/10, it means the solution contains 1/10th of the normal concentration.

The molarity of H2SO4 can be calculated as follows:

Molarity (M) = Normality (N) * Equivalent factor

Since H2SO4 is a diprotic acid, its equivalent factor is 2.

Molarity (M) = (N/10) * 2 = N/5

Now, let's calculate the number of moles of H2SO4:

Number of moles of H2SO4 = Molarity * Volume (in liters)
= (N/5) * (50/1000)
= N/1000

Step 2: Calculate the number of moles of NH3

Since H2SO4 reacts with NH3 in a 1:1 ratio, the number of moles of NH3 produced will be equal to the number of moles of H2SO4.

Number of moles of NH3 = Number of moles of H2SO4
= N/1000

Step 3: Calculate the number of moles of nitrogen

In the reaction, 1 mole of NH3 contains 1 mole of nitrogen. Therefore, the number of moles of nitrogen will be the same as the number of moles of NH3.

Number of moles of nitrogen = Number of moles of NH3
= N/1000

Step 4: Calculate the percentage of nitrogen

Percentage of nitrogen = (Number of moles of nitrogen / Total moles of substance) * 100

The total moles of the substance can be calculated using the molar mass of nitrogen:

Molar mass of nitrogen = 14 g/mol (approximately)

Total moles of substance = Mass of substance / Molar mass of nitrogen
= 0.295 g / 14 g/mol
≈ 0.02107 mol

Percentage of nitrogen = (N/1000 / 0.02107) * 100
= (N * 1000 / 0.02107)
≈ 47438.16 * N

Therefore, the percentage of nitrogen in the substance is approximately 47438.16 times the normality (N) of the H2SO4 used for neutralization.

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